Answer:
A. 6.282
B. 2.03kg
Explanation:
A.
We solve using archimedes principle
L³pwood = L²dwater
We make d subject of the formula
d = Lpwood/pester
= 18x651/1000
= 18x0.651
= 11.718cm
Distance from horizontal top to water level
= 18-11.718
= 6.282cm
B.
When we place lead block
WL + L³pwoodg = L³pwaterg
WL = L³g(Pwater-Pwood)
= 0.18³x9.8(1000-651)
= 19.94N
19.94/9.8
= 2.03kg
The mass m is therefore 2.03kg
Answer:
20 m/s
Explanation:
initial velocity, u= 25m/s
u has two components. one in horizontal and in one vertical.
so,
u sin theta = vertical component.
=> u sin theta = 25× 4/5
= 20 m/s
Answer:
Magnitude of the net force acting on the kayak = 39.61 N
Explanation:
Considering motion of kayak:-
Initial velocity, u = 0 m/s
Distance , s = 0.40 m
Final velocity, v = 0.65 m/s
We have equation of motion v² = u² + 2as
Substituting
v² = u² + 2as
0.65² = 0² + 2 x a x 0.4
a = 0.53 m/s²
We have force, F = ma
Mass, m = 75 kg
F = ma = 75 x 0.53 = 39.61 N
Magnitude of the net force acting on the kayak = 39.61 N
When plants make sugar it is called photosynthesis. Sugar is usually carried through parts of the plant by the vascular system. Most times the sugar is stored in the leaves of the plant, but another storage of the plant would be <span>moved into the phloem by active transport.</span>
Answer:
D) D = 
, E) (C, D) = ( 
Explanation:
Part D) two expressions are indicated
3C + 4D = 5
2C +5 D = 2
let's simplify each expression
3C + 4D = 5
4D = 5 - 3C
we divide by 4
D =
The other expression
2C +5 D = 2
2C = 2 - 5D
C = 
we can see that the correct result is 1
Part E.
It is asked to solve the problem by the substitution method, we already have
D =
we substitute in the other equation
2C +5 D = 2
2C +5 (5/4 - ¾ C) = 2
we solve
C (2 - 15/4) + 25/4 = 2
-7 / 4 C = 2 - 25/4
-7 / 4 C = -17/4
7C = 17
C = 
now we calculate D
D = 
D = 5/4 - 51/28
D =
D = - 16/28
D = 
the result is (C, D) = ( )
