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noname [10]
4 years ago
5

The International Electrotechnical Commission (IEC) is the predominant organization for developing and publishing international

standards for technologies related to electrical and electronic devices and processes.
A. True
B. False
Physics
1 answer:
anastassius [24]4 years ago
5 0

Answer:

The correct option is A (TRUE)

Explanation:

International Electrotechnical Commission (IEC) which was first formed in 1906 is the predominant organization for developing and publishing international standards for technologies related to electrical and electronic devices and processes. The standards developed by this association are widely used in scientific fields such as power generation, semiconductors, fibre optics, batteries, solar energy, nanotechnology and marine energy. They also proposed the International System of Units( SI unit) used in many fields of study today.

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An athlete with mass m running at speed v grabs a light rope that hangs from a ceiling of height H and swings to a maximum heigh
-Dominant- [34]

Answer:

d) The 2 athletes reach the same height, because the athletes run with the same speed.

Explanation:

In the whole process , kinetic energy is converted into potential energy .

1/2 m v² = mgh

v² = 2gh

h = v² / 2g

In this expression we see that height attained does not depend upon mass of the object . At the same time it also makes it clear that it depends upon velocity . As the velocity in both the cases are same , height attained by both of them will be same. Hence option d ) is correct.

7 0
3 years ago
The density (mass divided by volume) of pure water is 1.00 g/cm^3 that of whole blood is 1.05 g/cm^3 and the density of seawater
Stells [14]

Answer:

a) 5000 g

b) 5250 g

c) 5150 g

Explanation:

For easier calculations, the formulas will be converted from g/cm³ to kg/m³, and then back when we're done.

Density of pure water is 1 g/cm³

1 g/cm³ = 1 * 0.001/0.000001

1 g/cm³ = 1000 kg/m³, and thus,

Density of pure blood

1.05 g/cm³ = 1050 kg/m³

Density of seawater

1.03 g/cm³ = 1030 kg/m³

Recall that, Density = mass / volume, and as such, mass = density * volume.

Converting our volume from L to m³

1 m³ = 1000 L, and as such

1 L = 0.001 m³

5 L = 0.005 m³

Mass of pure water = 1000 * 0.005

Mass of pure water = 5 kg

Mass of pure blood = 1050 * 0.005

Mass of pure blood = 5.25 kg

Mass of seawater = 1030 * 0.005

Mass of seawater = 5.15 kg

Converting these masses back to g, we have

Mass of pure water = 5 kg * 1000 g

Mass of pure water = 5000 g

Mass of pure blood = 5.25 kg * 1000 g

Mass of pure blood = 5250 g

Mass of seawater = 5.15 kg * 1000 g

Mass of seawater = 5150 g

6 0
3 years ago
A particular heat engine has a mechanical power output of 4.00 kW and an efficiency of 26.0%. The engine expels 8.55 103 J of ex
Ivahew [28]

To develop the problem we will start by finding the energy taken by each cycle through the efficiency of the motor and the exhausted energy. Later the work will be found for the conservation of energy in which this is equivalent to the difference between the two calculated energy values. Finally the estimated time will be calculated with the work and the power given,

\text{Efficiency of the heat engine} = \eta = 26\% = 0.26

\text{Energy taken in by the heat engine during each cycle} = Q_h

\text{Energy exhausted by the heat engine in each cycle} = Q_c = 8.55*10^3 J

\eta = 1 - \frac{Q_{c}}{Q_{h}}

0.26 = 1 - \frac{8.55\ast 10^{3}}{Q_{h}}

\frac{8.55* 10^{3}}{Q_{h}} = 0.74

Q_h = \frac{8.55*10^3}{0.74}

Q_h = 11.554*10^3J

PART A)

Work done by the heat engine in each cycle = W

W = Q_h-Q_c

W = 11.554*10^3J-8.55*10^3J

W = 3004J

According to the value given we have that,

P = 4.0kW

P = 4000W

Power is defined as the variation of energy as a function of time therefore,

P = \frac{W}{t}

4000W = \frac{3004J}{t}

t = \frac{3004}{4000}

t = 0.75s

Therefore the interval for each cycle is 0.75s

5 0
3 years ago
How are Piaget and Erikson's theories different?
SOVA2 [1]
D) all of the above is the answer
8 0
3 years ago
Read 2 more answers
A student was asked to push a large box down the hallway about 35 meters. the task took the student five minutes and a force of
zaharov [31]
Rate of work or Power done by the student can be computed with below formulas.
1. Formula for Work
Work = Force x distance
Force or F = Force applied to the object 
distance or d = displacement

2. Formula for Power
P = Work done / Time it was done or completed

Substituting the values we have,
Work or Work done = 150 N x 35 meters = 5250 J (unit of work).

Lastly computing for the rate we have,
Power or rate of work = 5250 J / 300 seconds (or 5 min) = 17.5 Joule/S or Watts

Answer is 17.5 watts

5 0
3 years ago
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