Answer:
Explanation:
Potential energy is the energy stored within an object, due to the object's position, arrangement or state
Answer: Ahead of the plane as it drops the supplies
Explanation: i got it right.
(d) is increasing its velocity by 2.0 m/s every second.
An acceleration of 2 m/s² means that the object is is increasing its velocity by 2.0 m/s every second.
<h3>What is an acceleration?</h3>
The rate at which an object's velocity changes over a predetermined period of time is referred to as its acceleration. Acceleration is mathematically defined as an object's change in velocity divided by the amount of time it took for that change to occur.
The positive sign of the acceleration denotes a change in velocity that is positive and growing, whereas the negative sign denotes a change in velocity that is decreasing.
Consequently, an acceleration of 2 m/s² indicates that the object's velocity is increasing by 2 m/s every second.
Learn more about acceleration here:
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Answer:
A. Calculate vector
B. Update vector of each object
C. Update position of each object
Explanation:
Taking assumption of a system in which the forces are a function of the previous step's final position:
Firstly, we calculate the (vector) forces acting on the objects.
Secondly, Update the (vector) momentum of each object
(note: also update the velocity).
Thirdly, Update the (vector) position of each object.
The other operations are as follows;
i. select (dt),
ii. define mass,
iii. Put down constants,
iv. initialize variables, this would occur before the time-step loop is entered.
To replace all forces on a pipe by the equivalent force
T= 8× 50 = 400lb.in
M = 16.30 = 480lb.in
F₂ = 50lb
To calculate the polar moment of inertia of shaft is
J = π/π²×(R⁴-r⁴)
= π²/2×(0.875⁴ - 0.750⁴)
= 0.423in.³
To calculate the moment of inertia
J= 1/2(J)
=1/2 (0.423)
=0.21188in.³
To calculate shear flow
Qy= 2/3(R³-r³)
= 2/3(0.875³- 0.750³)
= 0.16536in.³
To calculate the thickness of the shaft
t= R-r = 0.875 - 0.750 = 0.125 in.
The stress due to torsions is.
Tx = TR/J = 400 × 0.875/0.42376
=825. 9psi.
The stress due to bending
Qx =My/T = 480 × 0.875/0.2118
=1982.3psi
The stress due to transverse shear
Qx = VQ/I(2t)
=50 × 0.16536/0.2118× 0.250
=156.1psi