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kaheart [24]
3 years ago
9

Roseanne and Jackie were asked to design and create a paper airplane that would stay in the air for as long as possible. They be

gan by folding printer paper into four different planes. They then test the flying time of the planes by throwing them and timing their flights with a stopwatch. They compared results to select the plane to use in the competition. According to the teacher's criteria, what data did Roseanne and Jackie MOST LIKELY use to select their best airplane?
how far the plane went
the planes times in the air
the plane with the lowest weight
Physics
1 answer:
jekas [21]3 years ago
6 0

Answer:

the planes times in the air

Explanation:

When a paper airplane is thown the path it takes is not the same every time. So, measuring the distance between the points where the airplane took off and the point where is landed would not show the time the plane was in the air.

The weight also does not determine the time the plane was in the air.

So, the planes air time recorded with the stopwatch gives the time the plane was in the air and will indicate the best plane.

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A 1000 kg car is rolling slowly across a level surface at 1m/s, heading toward a group of small innocent children.
Ne4ueva [31]

Answer:

The force is -1620.73 N.

Explanation:

Given that,

Mass of car = 1000 kg

Velocity = 1 m/s

Distance = 2 m

Angle = 30°

We need to calculate the force

Using formula of work done

W_{net}=K_{f}-K_{i}

F\times d=K_{f}-K_{i}

Fd\cos\theta=-K_{i}

F=\dfrac{-K_{f}}{d\cos\theta}

F=-\dfrac{\dfrac{1}{2}mv^2}{d\cos\theta}

Put the value into the formula

F=-\dfrac{\dfrac{1}{2}\times1000\times(1)^2}{2\times\cos30}

F=-1620.73\ N

Hence, The force is -1620.73 N.

7 0
4 years ago
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The process of heat radiation is the ONLY method of heat transfer that can occur _____.
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B) through space I am sorry if it is wrong
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A gray kangaroo can bound across a flat stretch of ground with each jump carrying it 10 m from the takeoff point. you may want t
Stells [14]

<u>Answer:</u>

Takeoff speed of Kangaroo = 12.91 m/s

<u>Explanation:</u>

  The distance reached by Kangaroo =  10 meter

  Angle at which it jumps = 18°

  The motion of Kangaroo is like a projectile, the distance traveled is the range of projectile.

   Range of projectile = Time taken for the projectile to reach ground* Horizontal velocity

   Time taken for the projectile to reach ground:

       Time taken = Two times of the time taken for the projectile to reach maximum height

       Time taken for the projectile to reach maximum height = Vertical speed / Acceleration = u sin θ/g

      Time taken for the projectile to reach ground = 2 u sin θ/g

  So Range of projectile = ucos\theta*\frac{2usin\theta}{g} =\frac{u^2sin2\theta}{g}

 We have Range = 10 meter, θ = 18⁰

    Substituting

        10=\frac{u^2sin(2*18)}{9.8}\\ \\ u^2= 166.73\\ \\ u=12.91 m/s

 Takeoff speed of Kangaroo = 12.91 m/s

3 0
3 years ago
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Algebraicallycalculate the rise time and fall timevalues for a sine wave at an arbitrary frequency f0(expressed in Hz). Assume t
Blababa [14]

Answer:

185.95 μsec

Explanation:

Given that:

Sine wave = Amsinw_{o}t

V_{min}=-V_{max}

Sinusodial signal f_{o}  = 50 kHz = 5*10^4Ht

Rise time is said to be defined as the time needed for a pulse to rise from 10% - 90% of maximum rate.

∴

t_1 = 10% = 0.1 Am

t_2 =90% = 0.9 Am

Using sine wave for  t_1; we have:

Amsinw_{o}t_1  = 0.1 Am

sinw_{o}t_1 = 0.1

w_{o}t_1 = sin^{-1}(0.1)

w_{o}t_1 = 5.7392

t_1=\frac{5.7392}{2 \pi f_0}

t_1=\frac{0.9134}{ f_0}

Using sine wave for t_2 ; we have:

Amsinw_{o}t_2  = 0.9 Am

sinw_{o}t_2  = 0.9

w_ot_2 = sin^{-1}(0.9)

w_ot_2 = 64.158

t_2 = \frac{64.1581}{2 \pi f_o}

t_2 = \frac{10.211}{f_o}

Change in rise time t_r = t_2 -  t_1

t_r = \frac{10.211}{f_o}-\frac{0.9134}{ f_0}

t_r = \frac{10.211-0.9134}{f_o}

t_r = \frac{9.2976}{f_o}

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t_r = \frac{9.2976}{5*10^4}

t_r = 1.85952 × 10⁻⁴

t_r = 185.952 × 10⁻⁶ sec

t_r =  185.95 μ sec

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