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Elza [17]
2 years ago
8

An elevator cab and its load have a combined mass of 1600 kg. Find the tension in the supporting cable when the cab, originally

moving downward at 12 m/s, is brought to rest with constant acceleration in a distance of 42 m.
Physics
1 answer:
amid [387]2 years ago
6 0

The tension in the supporting cable when the cab originally moves downward is 18422.4 N

What is tension?

Tension is described as the pulling force by the means of a three-dimensional object.

Tension might also be described as the action-reaction pair of forces acting at each end of said elements.

Here,

m =combined mass = 1600 kg

s = Displacement of the elevator = 42 m

g = Acceleration due to gravity = 9.81 m/s²

u = Initial velocity = 12 m/s

v = Final velocity = 0

According to the equation of motion:

v^{2} - u^{2} = 2as

0 - 12^2 = 2*a*42

a = - 144 / 84

a = - 1.714 m/s^2

Now let's write the equation of the forces acting on the elevator. Taking upward as positive direction:

T-mg = ma

T = m(g-a)

T = 1600 ( 9.8-(-1.74))

T=18422.4 N

Hence,

The tension in the supporting cable when the cab, originally moving downward is 18422.4 N

Learn more about tension here:

<u>brainly.com/question/13772148</u>

#SPJ4

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what is the potential difference across the headlight bulbs when the starter motor is operated, requiring an additional 39 a fro
frosja888 [35]

The starter motor's potential difference across the headlight bulbs is 38.45V, requiring an additional 39 a from the battery. Voltage, also known as potential difference.

It is sometimes described as the amount of work needed to move a test charge between two sites, expressed as a unit of charge. Volt is the potential difference's SI unit (V). We only take into account the charge between the locations P and Q when current moves between them in an electric circuit. Electric potential difference between two sites is referred to as voltage, also known as electric pressure, electric tension, or (electric) potential difference. an electric field that is static.

Vh = I*Rn

Vh = 39/5.476*5.40v

Vh = 38.45v

Learn more about voltage here

brainly.com/question/13521443

#SPJ4

5 0
1 year ago
A velocity selector has a magnetic field of magnitude 0.22 T perpendicular to an electric field of magnitude 0.51 MV/m.
ohaa [14]

Answer:

speed of a particle  = 2.31 × 10^{6} m/s

energy of proton required = 27.77 KeV

energy of electron required =  15.171 eV

Explanation:

given data

magnetic field of magnitude = 0.22 T

electric field of magnitude = 0.51 MV/m

to find out

speed of a particle and energy must protons have to pass through undeflected and  energy must electrons have to pass through undeflected

solution

we know that force due to magnetic and electric field is express as

force due to magnetic field B = qvB    ..............1

and force due to electric field E = qE   .....................2

so without deflection force due to magnetic field  = force due to electric field  

so here qvB = qE

and V = \frac{E}{B}    ...................3

put here value

V =  \frac{0.51*10^6}{0.22}

speed of a particle  = 2.31 × 10^{6} m/s

and

now energy of proton required will be here as

energy of proton required = mass of proton × \frac{V^2}{2}

put here value

energy of proton required = 1.67 × 10^{-27} × \frac{(2.31*10^6)^2}{2}

energy of proton required = 4.45 × 10^{-15} J

energy of proton required = 4.45 × 10^{-15} J ÷ (1.602 × 10^{-19}

energy of proton required = 27777.777 eV

energy of proton required = 27.77 KeV

and

now we get here energy of electron required that is

energy of electron required = mass of electron × \frac{V^2}{2}

put here value

energy of electron required = 9.11 × 10^{-31} × \frac{(2.31*10^6)^2}{2}

energy of electron required =  24.305× 10^{-19} J

energy of electron required =  24.305 × 10^{-19} J ÷ (1.602 × 10^{-19}  

energy of electron required =  15.171 eV

5 0
3 years ago
Read 2 more answers
I don’t know the answer <br><br> Help me please
lubasha [3.4K]

Answer:

Explanation:

i wanna say its B but if im wrong sorry i tried

5 0
3 years ago
All of the following are examples of mechanical energy except:
Paladinen [302]
The answer is B. The nuclei of elements.
8 0
3 years ago
What is the gravitational force between two bowling balls with 7kg mass each and 1.1m apart ?
Rufina [12.5K]

Answer:

2.7010 * 10^-9 N

Explanation:

solution;

mass (m1) = 7kg

mass (m2) = 7kg

distance(d) = 1.1m

universal gravitational constant (G) = 6.67 * 10^-11

we know that,

gravitational force = (G*m1*m2)/d^2

= ((6.67 * 10^-11) *7 *7)/(1.1)^2

=(3.2683 *10^-9)/1.21

= 2.7010 * 10^-9

Gravitational force = 2.7010 * 10^-9 N

8 0
3 years ago
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