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3 years ago

5

Which wave has a greater frequency?

2 answers:

DedPeter [7]3 years ago

8 0

The wave diagramed in blue.

miss Akunina [59]3 years ago

6 0

Answer:

The wave diagramed in blue.

Explanation:

The reason for this is because frequency is explained as the number of times something has occurred in a certain period of time.

Here, we are talking about wavelength, so the frequency is the number of times the wave can oscillate in this time length.

Say we make dots on the middle of each downward slope. How long does it take to get to each dot compared to the other diagram? The answer is the one with the least amount of time. The wave diagramed in blue.

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It takes work to push charge through a change of potential.
There's no change of potential along an equipotential path,
so that path doesn't require any work.

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Connecting many devices in a single socket does not affect the flow of current in a

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3 years ago

Two equal charges are separated by 3.7x10^-10m. The force between the charges has a magnitude of 2.37x10^-3 N. What is the magni

Alla [95]

Answer:

Charge on two particles is given as

$q = 1.89 \times 10^{-16} C$

Explanation:

As we know that the electrostatic force between two charges is given by formula

$F = \frac{Kq_1q_2}{r^2}$

so we will have

$q_1 = q_2 = q$

$r = 3.7 \times 10^{-10} m$

$F = 2.37 \times 10^{-3} N$

so we have

$2.37 \times 10^{-10} = \frac{(9 \times 10^{9})(q)(q)}{(3.7 \times 10^{-10})^2}$

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3 years ago

550 J of work must be done to compress a gas to half its initial volume at constant temperature. How much work must be done to c

Over [174]

Answer:

The amount of work that must be done to compress the gas 11 times less than its initial pressure is 909.091 J

Explanation:

The given variables are

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Thus the product of pressure and volume change = work done by gas, thus

P × -0.5V₁ = 500 J

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also P₁/V₁ = P₂/V₂ but V₂ = 0.5V₁ Therefore P₁/V₁ = P₂/0.5V₁ or P₁ = 2P₂

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Anastaziya [24]

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3 years ago