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3 years ago

10

Describe at least 1 advantage and 1 disadvantaged to learning about a scientific discovery from

1 answer:

Over [174]3 years ago

8 0

Answer:

A

Explanation:

You can get alot of info from it then again the info could be misleading

Answer:

B

Explanation:

You can get some good info from the internet but its most likely the wrong info

Answer:

c

Explanation:

It informs you with the info you need then again you are most likely getting socialy forced information.

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Why do we use the two-body problem to solve interplanetary trajectories, instead of including all of the appropriate gravitation

egoroff_w [7]

Answer:

ur mom

hsheu7shrbrjxbfbbrndnifidfjf

6 0

3 years ago

A pitcher throws a curveball that reaches the catcher in 0.64 s. The ball curves because it is spinning at an average angular ve

myrzilka [38]

Answer:

$\Delta \theta=19.44\ rad$

Explanation:

We just have to calculate what angular displacement a ball with an average angular velocity of 290 rev/min experiments in 0.64s. By definition, angular velocity $\omega$ is the angular displacement $\Delta \theta$ divided by the time elapsed:

$\omega=\frac{\Delta \theta}{\Delta t}$

Since $1\ rev=2\pi \ rad$ and $1\ min=60\ s$ , we can covert:

$\omega=290\ rev/min=\frac{290\ rev}{min}(\frac{1\ min}{60s})(\frac{2\pi \ rad}{1\ rev})=30.37\ rad/s$

Where the terms between parenthesis are equal to 1, so they just change the units. Then for our values we have:

$\Delta \theta=\omega \Delta t=(30.37\ rad/s)(0.64s)=19.44\ rad$

6 0

4 years ago

A pilot can withstand an acceleration of up to 9g, which is about 88 m/s2, before blacking out. What is the acceleration experie

sweet-ann [11.9K]

Answer:

Acceleration, $a=97.67\ m/s^2$

Explanation:

Given that,

Speed of pilot, v = 475 m/s

Radius of the circle, r = 2310 m

If the pilot is moving in a circular path, it will experience a centripetal acceleration. It is given by the formula as :

$a=\dfrac{v^2}{r}$

$a=\dfrac{(475\ m/s)^2}{2310\ m}$

$a=97.67\ m/s^2$

So, the acceleration experienced by a pilot flying in a circle is $97.67\ m/s^2$ . Hence, this is the required solution.

8 0

3 years ago

A 35 kg boy is riding a 65 kg go-cart. He pushes on the gas pedal, causing the cart to accelerate at 5 m/s2. Use the equation F

trasher [3.6K]

Answer:

$\boxed {\boxed {\sf 500 \ Newtons }}$

Explanation:

The equation for force is given:

$F=m*a$

First, we must find the total mass, which is the sum of the boy's mass and the go-cart's mass.

total mass= boy's mass + go cart's mass

The boy's mass is 35 kilograms and the go cart's is 65 kilograms.

total mass= 35 kg+ 65 kg=100 kg

Now we know the total mass and the acceleration.

$m= 100 \ kg \\a= 5 \ m/s^2$

Substitute the values into the formula.

$F=100 \ kg * 5 \ m/s^2$

Multiply.

$F= 500 \ kg*m/s^2$

1 kilograms meter per square second is equal to 1 Newton.
Our answer of 500 kg*m/s² is equal to 500 Newtons.

$F= 500 \ N$

The force exerted by the go cart engine is <u>500 Newtons.</u>

4 0

3 years ago

Read 2 more answers

A 12.0 V car battery is being used to power the headlights of a car. Each of the two headlights has a power rating of 41.8 Watts

Marina CMI [18]

Answer:

n = 4.35 x 10¹⁹

Explanation:

Given that

Voltage V= 12 V

Power rating of headlights = 41.8 W

We know that headlights of the car is connected in parallel connection.

We know that

Power = Current x Voltage

P = V I

$I=\dfrac{41.8}{12}\ A$

I=3.48 A

Therefore the total current will be

I'= 3.48 + 3.48 A

I = 6.96 A

We know that

Charge = Current x time

q= I' t

q= 6.96 x 1

q= 6.96 C

The charge on electron ,e= 1.6 x 10⁻¹⁹

q= n e

n=Number of electron

$n=\dfrac{q}{e}$

$n=\dfrac{6.96}{1.6\times 10^{-19}}$

n = 4.35 x 10¹⁹

5 0

4 years ago