To develop this problem we will start from the definition of entropy as a function of total heat, temperature. This definition is mathematically described as
![S = \frac{Q}{T}](https://tex.z-dn.net/?f=S%20%3D%20%5Cfrac%7BQ%7D%7BT%7D)
Here,
Q = Total Heat
T = Temperature
The total change of entropy from a cold object to a hot object is given by the relationship,
![\Delta S = \frac{Q}{T_{cold}}-\frac{Q}{T_{hot}}](https://tex.z-dn.net/?f=%5CDelta%20S%20%3D%20%5Cfrac%7BQ%7D%7BT_%7Bcold%7D%7D-%5Cfrac%7BQ%7D%7BT_%7Bhot%7D%7D)
From this relationship we can realize that the change in entropy by the second law of thermodynamics will be positive. Therefore the temperature in the hot body will be higher than that of the cold body, this implies that this term will be smaller than the first, and in other words it would imply that the magnitude of the entropy 'of the hot body' will always be less than the entropy 'cold body'
Change in entropy
is smaller than ![\Delta S_{cold}](https://tex.z-dn.net/?f=%5CDelta%20S_%7Bcold%7D)
Therefore the correct answer is C. Will always have a smaller magnitude than the change in entropy of the cold object
No two electrons can have the same set of quantum numbers .
<h3>What is Wolfgang Pauli hypothesized an exclusion principle?</h3>
Pauli made a significant advance when he proposed the notion of adding a fourth quantum number to the three that were previously used to represent the quantum state of an electron. Physically speaking, the first three quantum numbers made sense since they had to do with how the electron moved about the nucleus.
The following rule was developed by Austrian physicist Wolfgang Pauli. The quantum numbers of any two electrons cannot be identical.
To put it another way, no two electrons can be in the same state. The Pauli exclusion principle is the name given to this proposition since it forbids electrons from being in the same state.
to learn more about exclusion principle go to - brainly.com/question/90573
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Answer:
0.34 m
Explanation:
From the question,
v = λf................ Equation 1
Where v = speed of sound, f = frequency, λ = Wave length
Make λ the subject of the equation
λ = v/f............... Equation 2
Given: v = 340 m/s, f = 500 Hz.
Substitute these values into equation 2
λ = 340/500
λ = 0.68 m
But, the distance between a point of rarefaction and the next compression point, in the resulting sound is half wave length
Therefore,
λ/2 = 0.68/2
λ/2 = 0.34 m
Hence, the distance between a point of rarefaction and the next compression point, in the resulting sound is 0.34 m
Answer:
Answer: It allows people to rapidly heat items
Hope this helps!
Explanation: