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Andreas93 [3]
3 years ago
13

Przykładny wykorzystania wodorotlenku amonu

Chemistry
1 answer:
Sergio [31]3 years ago
7 0

W produkcji żywności stosuje się wodorotlenek amonu jako środek spulchniający

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What is a mole?
fredd [130]

Answer:

B.

Explanation:

One mole is the amount of substance that contain the Avogadro number which is equal to 6.022×10^23 atom, molecules or ions.

7 0
3 years ago
A neutron has a mass A. that is less than the mass of an electron. B. that is about equal to the mass of an electron. C. that is
soldi70 [24.7K]

Answer:

Option C:- that is equal to mass of an proton.

Explanation:

Protons and neutrons have approximately the same mass, about 1.67 × 10-24 grams, which scientists define as one atomic mass unit (amu) or one Dalton. While electron has mass of 9.31 ×10⁻¹⁹.

6 0
3 years ago
Calculate each of the following quantities:<br> (a) Total number of ions in 38.1 g of SrF₂
adelina 88 [10]

The total number of ions in 38.1 g of SrF₂ is 5.479 x 10²³.

<h3>What are ions?</h3>

Ions are the elements with a charge on them. It happens when they share electrons with other atoms to form a compound.

We have to calculate the total number of ions in 38.1 g of .

The molar mass of SrF₂ = 125.62 g/mol

The number of moles = 38.1 g of  1.0 mol / 125.62  = 0.30329 moles

Given that, total moles of SrF₂ ions in  = 1.0 mol of + 2.0 moles of  = 3.0 moles

Total moles of ions in 0.30329 moles of

= (0.30329 moles of SrF₂) x 3.0 / 1.0  = 0.90988 mol ions

We know that,

1.0 mole of ions = 6.023 x 10²³ ions

Thus, the number of total ions = ( 0.90988 mol ions) x  6.023 x 10²³ / 1.0 mol = 5.479 x 10²³ ions

Thus, the number of ions is in 38.1 g of 5.479 x 10²³ ions

To learn more about ions, refer to the link:

brainly.com/question/14295820

#SPJ4

8 0
1 year ago
What volume of lead (of density 11.3 g/cm3 ) has the same mass as 395 cm3 of a piece of redwood (of density 0.38 g/cm3 )? Answer
Zepler [3.9K]
d_{1}=\frac{m}{V_{1}}\\\\&#10;V_{1}=395cm^{3}\\&#10;d_{1}=0,38\frac{g}{cm^{3}} \ \ \ \ \Rightarrow \ \ \ \ m=395cm^{3}*0,38\frac{g}{cm^{3}}=150,1g\\\\\\&#10;d_{2}=\frac{m}{V_{2}}\\\\&#10;m=150,1g\\&#10;d_{2}=11,3\frac{g}{cm^{3}} \ \ \ \ \Rightarrow \ \ \ \ V_{2}=\frac{150,1g}{11,3\frac{g}{cm^{3}}}\approx13,28cm^{3}
8 0
3 years ago
Ethanol has a density of 0.789 g/cm3. What is the mass of 423 cm3 of ethanol? M = (D)(V)
Ivahew [28]

Answer:

<h2>The answer is 334 g</h2>

Explanation:

The mass of a substance when given the density and volume can be found by using the formula

<h3>mass = Density × volume</h3>

From the question

volume of ethanol = 423 cm³

density = 0.789 g/cm³

So we have

mass = 0.789 × 423 = 333.747

We have the final answer as

<h3>334 g</h3>

Hope this helps you

6 0
3 years ago
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