Answer is: the molarity of HCl found in a titration is 0.1 M.
Balanced chemical reaction between hydrochloric acid and sodium hydroxide:
HCl(aq) + NaOH(aq) → NaCl(aq) + H₂O(l).
From balanced chemical reaction: n(HCl) : n(NaOH) = 1 : 1.
n(HCl) = n(NaOH).
c(HCl) · V(HCl) = c(NaOH) · V(NaOH).
c(HCl) = c(NaOH) · V(NaOH) ÷ V(HCl).
c(HCl) = 0.1 M · 50 ml ÷ 50 ml.
c(HCl) = 0.1 M; molarity of hydrochloric acid.
Answer: There are 6 different outcomes.
Explanation:
There are two options for procedure one (one or two steps) and three options for procedure two (one, two or three steps). If we multiply those options , the result is the total number of outcomes for the analysis.
2 x 3 = 6
These being
- One step on procedure one and one step on procedure two
- One step on procedure one and two steps on procedure two
- One step on procedure one and three steps on procedure two
- Two steps on procedure one and one step on procedure two
- Two steps on procedure one and two steps on procedure two
- Two steps on procedure one and two steps on procedure two
NH3 because the molecule in the room is more solid than and room temperature
Answer:
Less than 7 ph value are acidic. Greater than 7 ph value are basic.
