Answer:
See Explanation
Explanation:
Metallic bonds involve attraction between electrons and positively charged metal ions. The metals are ionized and electrons form a sea of valence electrons. These loosely bound electrons surround the nuclei of the metals.
The presence of this sea of electrons explains the fact that metals conduct electricity and heat due to the free valence electrons.
Due to the nature of the bonding between metal atoms,metals are malleable and ductile.
Due to the strong electrostatic interaction between metal ions and electrons, the metallic bond is very strong and is very difficult to break thereby accounting for the greater strength of metals as the size of the metallic ion decreases.
3 L will be the final volume for the gas as per Charle's law.
Answer:
Explanation:
The kinetic theory of gases has two significant law which forms the backdrop of motion of gases. They are Charle's law and Boyle's law. As per Charle's law, the volume of any gas molecule at constant pressure is directly proportional to the temperature of the molecule.
V∝ T
Since, here two volumes are given and at two different temperatures with constant pressure. Then as per Charle's law, the relation between the volumes of air at different temperature will be
![\frac{V_{1} }{T_{1} }= \frac{V_{2} }{T_{2} }](https://tex.z-dn.net/?f=%5Cfrac%7BV_%7B1%7D%20%7D%7BT_%7B1%7D%20%7D%3D%20%5Cfrac%7BV_%7B2%7D%20%7D%7BT_%7B2%7D%20%7D)
So in this case, V1 = 6 L and T1 = 80° C. Similarly, T2 = 40° C. So we have to determine the V2.
![\frac{6}{80}=\frac{V_{2} }{40}](https://tex.z-dn.net/?f=%5Cfrac%7B6%7D%7B80%7D%3D%5Cfrac%7BV_%7B2%7D%20%7D%7B40%7D)
![V_{2}=\frac{6*40}{80}=3 L](https://tex.z-dn.net/?f=V_%7B2%7D%3D%5Cfrac%7B6%2A40%7D%7B80%7D%3D3%20L)
So, 3 L will be the final volume for the gas as per Charle's law.
Answer:
The molar mass of Mg(NO₃)₂, 148.3 g/mol.
Explanation:
Step 1: Given data
- Mass of Mg(NO₃)₂ (solute): 42.0 g
- Volume of solution: 259 mL = 0.259 L
Step 2: Calculate the moles of solute
To calculate the moles of solute, we need to know the molar mass of Mg(NO₃)₂, 148.3 g/mol.
42.0 g × 1 mol/148.3 g = 0.283 mol
Step 3: Calculate the molarity of the solution
M = moles of solute / liters of solution
M = 0.283 mol / 0.259 L
M = 1.09 M