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myrzilka [38]
3 years ago
13

A object is 200 miles from the center of a circle and makes a circuit every 2 hours. How fast is it moving?

Physics
1 answer:
Tanya [424]3 years ago
4 0

Answer: 628.31 miles/h

Explanation:

The equation to calculate the average speed s of an object moving in a circular path is:

s=\frac{2 \pi r}{T} (1)

Where:

r=200 miles is the radius of the circumference

T=\frac{1}{f} is the period, which has an inverse relation with the frequency f=\frac{1 circuit}{2 h}=0.5 h^{-1}. Then T=\frac{1}{0.5 h^{-1}}=2 h

Solving the equation:

s=\frac{2 \pi (200 miles)}{2 h} (2)

s=628.31 miles/h (3)

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The velocity, expressed in terms of  ME, RE is given as V_0 = \sqrt{98.99R_E}.

The maximum height that the rocket could reach if launched vertically is H = (¹/₂v₀²)/g.

<h3>Maximum height of the rocket</h3>

The maximum height reached by the rocket can be modeled using conservation of energy as shown below;

P.Ei + K.Ei = K.Ef + P.Ef

M_EgR_E + \frac{1}{2} M_EV_0^2= \frac{1}{2} M_E(\frac{V_o}{10} )^2+ M_Eg(6R_E)\\\\\frac{1}{2} M_EV_0^2 - \frac{1}{2} M_E(\frac{V_o}{10} )^2 = M_Eg(6R_E) - M_EgR_E\\\\0.495M_EV_0^2= 5gM_ER_E\\\\0.495V_0^2= 5gR_E\\\\V_0 = \sqrt{\frac{5gR_E}{0.495} } \\\\V_0 = \sqrt{98.99R_E}

<h3>Maximum height when it is launched vertically</h3>

P.E = K.E

mgH = ¹/₂mv²

H = (¹/₂v₀²)/g

Learn more about conservation of energy here: brainly.com/question/166559

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3 years ago
The small metal cylinder has a mass of 0.20 kgkg, the coefficient of static friction between the cylinder and the turntable is 0
deff fn [24]

Answer:

velocity of the metal cylinder = 0.343 m/s

Explanation:

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