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lidiya [134]
3 years ago
5

A 1210 kg rollercoaster car is

Physics
1 answer:
ratelena [41]3 years ago
3 0

Answer: 4.98 m/s

Explanation:

You solve these kinetic energy, potential energy problems by using the fact P.E.+ K.E. = a constant as long as friction is ignored.

PEi = 0 in this case

KEi = ½mVi² = PEf+KEf = mghf + ½mVf²

½1210*8.31² = 1210*9.8*2.26 + ½1210*Vf²

½1210*Vf² = ½1210*8.31² - 1210*9.8*2.26

Vf² = 8.31² - 2*9.8*2.26 = 4.98² so Vf = 4.98m/s

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Answer:

Vy = V0 sin 38       where Vy is the initial vertical velocity

The ball will accelerate downwards (until it lands)

Note the signs involved   if Vy is positive then g must be negative

The acceleration is constant until the ball lands

t (upwards) = (0 - Vy) / -g      = Vy / g      final velocity = 0

t(downwards = (-Vy - 0) / -g = Vy / g      final velocity = -Vy

time upwards = time downwards     (conservation laws)

8 0
2 years ago
Velocity is described by __ and time
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4 0
3 years ago
An electric field of magnitude 2.35 V/m is oriented at an angle of 25.0° with respect to the positive z-direction. Determine the
zzz [600]

Answer:

The magnitude of the electric flux is 3.53\ N-m^2/C

Explanation:

Given that,

Electric field = 2.35 V/m

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We need to calculate the flux

Using formula of the magnetic flux

\phi=E\cdot A

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E = electric field

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\phi=2.35\times1.65\times0.91

\phi=3.53\ N-m^2/C

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8 0
3 years ago
The acceleration of an object is constant when its velocity is :
emmasim [6.3K]

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B. changing by a constant amount each second

Explanation:

thats my answer

5 0
3 years ago
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