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3 years ago

How does the jet stream affect the movement of air masses

Physics

1 answer:

ryzh [129]3 years ago

5 0

Answer:

See the explanation below.

Explanation:

Jet streams are defined as the fast flowing meandering air currents in the atmosphere, they generally flow around ten kilometers from above the Earth's surface and form at the boundaries of two air masses which have significant temperature difference within them, greater the temperature difference more significant and fast flowing will be the jet streams. Jet streams have a key role in determining the weather of given region as it separates warmer air mass with the colder air mass and hence move the weather system to new areas and sometimes it even stops at any particular place therefore determining or affecting the weather condition of the region. Depending upon seasons and other factors such as position of sun these jet streams also shift their patterns, for example, Weather and climatic condition of United Kingdom is largely affected by the movement of these Jet streams.

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A uniform solid cylindrical log begins rolling without slipping down a ramp that rises 28.0° above the horizontal. After it has

Novay_Z [31]

Answer:

3.07 m/s

Explanation:

6 0

3 years ago

A satellite is spinning at 6.0 rev/s. The satellite consists of a main body in the shape of a sphere of radius 2.0 m and mass 10

bearhunter [10]

Answer:

605447.7066 kgm²/s

Explanation:

$m_1$ = Mass of sphere = 10000 kg

$m_2$ = Mass of rod = 10 kg

r = Radius of sphere = 2 m

l = Length of antenna = 3 m

Angular speed

$\omega=6\times 2\pi\\\Rightarrow \omega=37.69911\ rad/s$

Angular momentum is given by

$L=I\omega$

Moment of inertia of the satellite is

$I_s=\frac{2}{5}m_1r^2$

Moment of antenna of the satellite is

$I_a=\frac{1}{3}m_2l^2$

The angular momentum of the system is

$L=I_s\omega+I_a\omega\\\Rightarrow L=\left(\frac{2}{5}m_1r^2+2\times \frac{1}{3}m_2l^2\right)\omega\\\Rightarrow L=\left(\frac{2}{5}10000\times 2^2+2\times \frac{1}{3}\times 10\times 3^2\right)\times 37.69911\\\Rightarrow L=605447.7066\ kgm^2/s$

The angular momentum of the satellite is 605447.7066 kgm²/s

5 0

3 years ago

if you stand on one side of a strike-slip fault and the block on the other side of the fault has moved to your left, this is kno

katrin [286]

If you stand on one side of a strike-slip fault and the block on the other side of the fault has moved to your left, this is known as a(n) left lateral fault.

There are several distinct sorts of fault lines, and they are called based on the fault's movement and the fault plane's own direction. These faults may be found all over the world, but the most active and earthquake-producing ones are in the Pacific Ocean's Ring of Fire region.

When you gaze along the length of a fault line, the left side will move toward you while the right side moves away from you. This is referred to as a left-lateral fault.

To know more about left lateral fault visit : brainly.com/question/14136640

#SPJ4

3 0

1 year ago

27. (a) What magnification is produced by a 0.150 cm focal length microscope objective that is 0.155 cm from the object being vi

denpristay [2]

Answer:

magnification = - 30

overall magnification = -240

Explanation:

given data

Focal length of microscope objective f = 0.150 cm

Object distance from microscope objective do = 0.155 cm

magnification by eyepiece = 8 ×

to find out

What magnification is produced and overall magnification

solution

we consider here Image distance from microscope objective is = di

so that

Magnification produced by objective will be = - $\frac{di}{do}$

so we find here di by given equation that is

$\frac{1}{do} +\frac{1}{di} = \frac{1}{f}$ ..................1

$\frac{1}{di} = \frac{1}{0.150} - \frac{1}{0.155}$

di = 4.65 cm

so that magnification by object will be

magnification = - $\frac{di}{do}$

magnification = - $\frac{4.65}{0.155}$

magnification = - 30

and

overall magnification will be

overall magnification = magnification by objective × magnification by eyepiece ........................2

overall magnification = -30 × 8

overall magnification = -240

7 0

3 years ago

When a parallel-plate capacitor is connected to a battery: a ___ is stored on one plate, and a ____ is stored on the other.

Ronch [10]

Answer:

a.) negative charge, positive charge

Explanation:

In order to solve this problem, we will need to see the image that can be seen in the attached image.

The point a has a higher potential than point B of the resistance R as the current flows from a to b.

The positive plate of capacitor b has higher potential than the negative plate c.

Once the capacitor has been charged to the nominal value, it will have the same potential of the battery, its terminals will open interrupting the flow of current. But keeping the potential or voltage differential through its points. This will allow the capacitor to work as a battery while discharging.

3 0

3 years ago