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sergij07 [2.7K]
3 years ago
9

If the magnetic field of an electromagnetic wave is in the +x-direction and the electric field of the wave is in the +y directio

n, the wave is traveling in what direction? Explain your answer.
Physics
1 answer:
alexandr1967 [171]3 years ago
7 0

Answer:

Explanation:

The direction of propagation of electromagnetic wave

is given by the direction of vector E x B where E is electrical field , B is magnetic field .

Given Electric field  = E i because it is along x axis

Magnetic field = Bj because it is along y axis

E x B = Ei x Bj

= EB k .

so direction of E  x B is along k direction or z  - axis so wave is propagating along z - axis .

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Ask Your Teacher An electric utility company supplies a customer's house from the main power lines (120 V) with two copper wires
natta225 [31]

Answer:

The potential difference at the customer's house is 117.1 V.

Explanation:

a) The potential difference at the customer's house can be calculated as follows:

\Delta V_{h} = \Delta V_{p} - \Delta V_{l}

<u>Where</u>:

V_{h}: is the potential difference at the customer's house

V_{p}: is the potential difference from the main power lines = 120 V

V_{l}: is the potential difference from the lines

\Delta V_{h} = \Delta V_{p} - IR

The resistance, R, is:

\frac{0.109 \Omega}{300 m}*2*34.0 m = 0.025 \Omega

Now, the potential difference at the customer's house is:

\Delta V_{h} = 120 V - 116A*0.025 \Omega = 117.1 V

Therefore, the potential difference at the customer's house is 117.1 V.

I hope it helps you!

4 0
3 years ago
When two or more forces act on an object at the same time what are they called
Vilka [71]

Unbalanced forces is what they are called

7 0
3 years ago
Why is the meteor shower is best observed after midnight?​
harkovskaia [24]

Answer:

At dawn your location on earth is pointed straight in the direction of the Earth's travel in its orbit.  Between midnight and dawn you are moving head-on through the location of the meteors in space, which means that you will, on average, observe more of them.

- public.nrao.edu

Explanation:

hope this helps

4 0
3 years ago
A spring with k = 500 N/m stores 704 J. How far is it extended from the equilibrium position
kaheart [24]

Given that:

k = 500 n/m,

work (W) = 704 J

spring extension (x) = ?

         we know that,

                      Work = (1/2) k x²

                          704 = (1/2) × 500 × x²

                            x = 1.67 m

A spring stretched for 1.67 m distance.

4 0
3 years ago
The density of a material in CGS system of units is 4g cm-³. In a system of units in which unit of length is 10 cm and unit of m
butalik [34]

\sf\underline{Solution:}

Here , the density of the material is 4g cm³ but it is not given in CGS system.

$\sf{As\:we\:know\:that:}$

$\sf\bold{Density=}$ $\sf\dfrac{Mass}{Volume}$

$\space$

\sf{Now,according \: to \:the\:question:}

$\sf\small{Density\:of\:the\:material=4}$ $\sf\dfrac{g}{cm^2}$

$\space$

$\sf{It\:is\:given\:that:}$

In the system of units the mass is 100gram.

$\space$

Hence,

$\sf{The\:mass\:unit\:for\:4g=}$ $\sf\dfrac{4}{100}$ $\sf{units}$

$\space$

In the system of units,the length is 10cm.

Henceforth,

$\sf\small{The\:length \:for\:1cm\:units=}$ $\sf\dfrac{1}{10}$ $\sf{units}$

$\space$

<u>☆</u><u> </u><u>Substitute</u><u> </u><u>the</u><u> </u><u>required</u><u> </u><u>values</u><u> </u><u>in</u><u> </u><u>the</u><u> </u><u>given</u><u> </u><u>formula</u><u>-</u>

$\sf\purple{Density=}$ $\sf\dfrac\purple{Mass}\purple{volume}$

$\space$

$\sf\underline\bold{Density\:of\:the\:material:}$

= $\sf\dfrac{4/100}{1/10^3}$ $\sf\bold{units}$

$\space$

= $\sf\dfrac{4/100}{1/1000}$ $\sf\bold{units}$

$\space$

= $\sf\dfrac{4000}{100}$ $\sf\bold{units}$

$\space$

$\sf\underline\bold\blue{=40\:units}$

$\sf\small{Therefore,option\:2nd\:is\:correct!}$

_______________________________

6 0
2 years ago
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