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sergij07 [2.7K]
3 years ago
9

If the magnetic field of an electromagnetic wave is in the +x-direction and the electric field of the wave is in the +y directio

n, the wave is traveling in what direction? Explain your answer.
Physics
1 answer:
alexandr1967 [171]3 years ago
7 0

Answer:

Explanation:

The direction of propagation of electromagnetic wave

is given by the direction of vector E x B where E is electrical field , B is magnetic field .

Given Electric field  = E i because it is along x axis

Magnetic field = Bj because it is along y axis

E x B = Ei x Bj

= EB k .

so direction of E  x B is along k direction or z  - axis so wave is propagating along z - axis .

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Gases, just like liquids are made of particles which can be further classified as atoms or molecules,
olga_2 [115]

Answer:

True

Explanation:

Solids, Liquids, and Gases are all make up of <u><em>atoms and molecules. </em></u>

8 0
3 years ago
A certain lightbulb has a tungsten filament with a resistance of 26 Ω when cold and 170 Ω when hot. If the equation R = R0 [1 +
iris [78.8K]

Answer:

Explanation: The equation that relates resistance of tungsten at different temperatures is as follows

R = R₀ [1 + α ∆T]  , R₀ is resistance at lower temperature , R is resistance at higher temperature . α is temperature coefficient of resistivity and ∆T is rise in temperature .

Putting the values

170 = 26 [1 + .0045 ∆T]

∆T = 1230.75

lower temperature = 40◦C

higher temperature = 1230 + 40

= 1270◦C

5 0
3 years ago
Rahman drops two stones P and Q each of mass 1 kg and 2 kg simultaneously from
kolbaska11 [484]

This question involves the use of the equations of motion for vertical motion.

The time taken by the stones P and Q to reach the ground is the same, that is "2 s".

The velocity with which Q hits the ground is "20 m/s".

The time taken by the stones to reach the ground can be calculated by using the second equation of motion for the vertical motion:

h = v_it+\frac{1}{2}gt^2

For both the stones P and Q:

h = height = 20 m

v_i = initial velocity = 0 m/s

t = time = ?

g = acceleration due to gravity = 10 m/s²

Therefore,

20\ m = (0\ m/s)t+\frac{1}{2}(10\ m/s^2)(t)^2\\\\t = \sqrt{\frac{20\ m}{5\ m/s^2}}

<u>t = 2 s</u>

<u></u>

Hence, the time taken by both the stones to reach the ground <u>is the same</u>.

To find the final velocity of stone Q we will use the first equation of motion for the vertical motion:

v_f=v_i+gt\\v_f = 0\ m/s+(10\ m/s^2)(2\ s)\\v_f = 20\ m/s

Learn more about equations of motion here:

brainly.com/question/20594939?referrer=searchResults

The attached picture shows the equations of motion in the horizontal and vertical directions.

5 0
2 years ago
The amount of gravitational pull an object experiences is its<br> a mass<br> b density
nata0808 [166]

The amount of gravitational pull an object experiences is its mass

<h3>What is Weight ?</h3>

Weight can be define as gravitational pull an object. It is a product of mass and acceleration due to gravity. That is, W = mg. It is measured in Newton (N)

The amount of gravitational pull an object experiences is its mass and not  density because the weight of an object depend on its mass and acceleration due to gravity.

W = mg

where

  • W = weight
  • m = mass
  • g = acceleration due to gravity

Therefore, the amount of gravitational pull an object experiences is its mass

Learn more about Weight here: brainly.com/question/19753744

#SPJ1

7 0
1 year ago
A 50.0 mg sample of an unknown radioactive substance was placed in storage and its mass measured periodically. After 19.7 days,
PilotLPTM [1.2K]
<h2>Answer: 4.928 days </h2><h2 />

Explanation:

This problem can be solved using the <u>Radioactive Half Life Formula: </u>

<u></u>

A=A_{o}.2^{\frac{-t}{h}} (1)

Where:

A=3.13mg is the final amount of the material

A_{o}=50mg is the initial amount of the material

t=19.7days is the time elapsed

h is the half life of the material (the quantity we are asked to find)

Knowing this, let's substitute the values and find h from (1):

3.13mg=(50mg)2^{\frac{-19.7days}{h}} (2)

\frac{3.13mg}{50mg}=2^{\frac{-19.7days}{h}} (3)

Applying natural logarithm in both sides:

ln(\frac{3.13mg}{50mg})=ln(2^{\frac{-19.7days}{h}}) (4)

-2.77=-\frac{19.7days}{h}ln(2) (5)

Clearing h:

h=\frac{-19.7days}{-2.77}(0.693) (6)

Finally:

h=4.928days

6 0
3 years ago
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