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Cerrena [4.2K]
3 years ago
8

A substance has a density of 4.5 g/cm3. The substance is heated and its density recalculated. What is the newly recorded density

?
Chemistry
1 answer:
Dmitry_Shevchenko [17]3 years ago
6 0

Answer:

Aluminum

Explanation:

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How do van der waals forces hold molecules together?
IRINA_888 [86]

Answer:

Electrostatic Van de Waals forces act between molecules to form weak bonds. The types of Van der Waals forces, strongest to weakest, are dipole-dipole forces, dipole-induced dipole forces and the London dispersion forces. The hydrogen bond is based on a type of dipole-dipole force that is especially powerful. These forces help determine the physical characteristics of materials.

4 0
4 years ago
W7L5 Stoichiometry Practice 2
Rzqust [24]

Answer:

.079 moles of Nirogen gas (N2)

Explanation:

You can see from the equaton that each ONE mole of N2 produces TWO moles of NH3.

 Find the number of moles of NH3 produced.

    Using Periodic Table : Mole wt of NH3 = 17 gm/mole

          2.7 gm / 17 gm/mole = .1588 moles

      One half as many moles of N2 are needed  = .079 moles

6 0
3 years ago
What is the density of a substance that has a volume of 14 millimeters and a mass of 13.2 grams.
Contact [7]

Answer:

<h2>0.94 g/mL</h2>

Explanation:

The density of a substance can be found by using the formula

density =  \frac{mass}{volume} \\

From the question we have

density =  \frac{13.2}{14}  \\  = 0.94285...

We have the final answer as

<h3>0.94 g/mL</h3>

Hope this helps you

6 0
3 years ago
I need help with the question please help
Irina18 [472]

Answer:

Explanation:

u are right

8 0
3 years ago
Read 2 more answers
Given the following reaction: NH4SH (s) &lt;--&gt; NH3 (g) + H2S (g) If we start
almond37 [142]

Answer:

D. 0.3 M

Explanation:

                                              NH4SH (s)      <-->            NH3 (g) + H2S (g)

Initial concentration              0.085mol/0.25L             0                 0

Change in concentration     -0.2M                               +0.2 M        +0.2M

Equilibrium               0.035mol/0.25 L=0.14M             0.2M           0.2M

concentration

Change in concentration (NH4SH) = (0.085-0.035)mol/0.25L =0.2M

K = [NH3]*[H2S]/[NH4SH] = 0.2M*0.2M/0.14M ≈ 0.29 M ≈ 0.3M

4 0
3 years ago
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