Azeotropic mixture. I think
Answer:
Below
Explanation:
2) there are 28 protons in this isotope
The number that is on the bottom of the "stacked pair" tells you how many protons are in this isotope. It is often represented by the variable Z.
3) there are 35 neutrons in this isotope
Subtract the number of protons (28) from the top number
4) there are 28 electrons in the neutral element of Nickel
If you were to look at the period table and find Ni, you would see that its atomic number is 28. This number tells us the amount of protons and electrons there are in that element.
5) 62.9296694 atomic mass units
Just search it up (unless your teacher wants you to calculate it)
6) there are 92 protons in this isotope
Again just look at the Z value to find the proton count
7) there are 146 neutrons in this isotope
Subtract 238 - 92 = 146
8) there are 92 electrons in the neutral element of uranium
Again just look at the periodic table and find U
9) 238.0507882 atomic mass units
10) 12C or carbon 12 is more likely to bond with oxygen that 14c carbon 14
This is because 12C is more abundant at 98.93% than 14C
Hope this helps! Best of luck <3
<span>351.4020 g/mol which is 3.51 x 10</span>∧ 2 g/mole
Atomic number = No. of proton = 1
so, your answer is 1
For this problem we can use half-life formula and radioactive decay formula.
Half-life formula,
t1/2 = ln 2 / λ
where, t1/2 is half-life and λ is radioactive decay constant.
t1/2 = 8.04 days
Hence,
8.04 days = ln 2 / λ
λ = ln 2 / 8.04 days
Radioactive decay law,
Nt = No e∧(-λt)
where, Nt is amount of compound at t time, No is amount of compound at t = 0 time, t is time taken to decay and λ is radioactive decay constant.
Nt = ?
No = 1.53 mg
λ = ln 2 / 8.04 days = 0.693 / 8.04 days
t = 13.0 days
By substituting,
Nt = 1.53 mg e∧((-0.693/8.04 days) x 13.0 days))
Nt = 0.4989 mg = 0.0.499 mg
Hence, mass of remaining sample after 13.0 days = 0.499 mg
The answer is "e"
