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2 years ago

the characteristic ions present in water solutions of acids are A) oxide ions B) chloride ions C)hydronium ions D)nitride ions

Chemistry

1 answer:

Tanzania [10]2 years ago

4 0

The characteristic ions present in the water solutions of acids are hydronium ions.

Option C

<u>Explanation:</u>

Ions are nothing but the oxidized or reduced state of any element in the periodic table. If an element loses electrons or if it gains electrons, then that element will be termed as ion instead of atoms. Water is composed of hydrogen [H⁺] ion and hydroxide ion [OH⁻] ion.

When water is mixed with acids, then H₂O will get combine with OH⁻ group leading to the formation of hyronium ion H₃O⁺ ion. So every acid when dissolved in water solution, they will be forming hydronium ion.

Thus, the characteristic ions present in water solutions of acids are hydronium ions.

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The orbital radius of Venus is 0.72 AU. What is this distance in kilometers? (One AU is about 150 million kilometers.)

Evgen [1.6K]

<span>The answer is D) 108 million kilometers. To solve this problem, you must perform a simple unit conversion calculation. 1 AU = 150,000,000 km is the conversion factor. Take the radius of Venus, .72 AU, and multiply it by 150,000,000 km/1 AU. You flip the conversion factor so that the units of the original distance in the numerator cancel the units in the denominator of the conversion factor. completing the calculation gives you 108,000,000 km</span>

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2 years ago

A sodium ion, Na+, with a charge of 1.6×10−19C and a chloride ion, Cl− , with charge of −1.6×10−19C, are separated by a distance

sasho [114]

Answer:

$W\geq 2.1x10^{-19}J$

Explanation:

Due to Coulomb´s law electric force can be described by the formula $F=K\frac{q_{1}.q_{2}}{r^{2}}$ , where K is the Coulomb´s constant ( $9x10^{9} N\frac{m^{2} }{C^{2} }$ ), $q_{1}$ = Charge 1 (Na+ in this case), $q_{2}$ is the charge 2 (Cl-) and r is the distance between both charges.

Work made by a force is W=F.d and total work produced is the change in energy between final and initial state. this is $W=W_{f} -W_{i}$ .

so we have $W=W_{f} -W_{i} =(K\frac{q_{(Na+)}q_{(Cl-)}rf}{r_{f} ^{2}})-(K\frac{q_{(Na+)}q_{(Cl-)}ri}{r_{i} ^{2}})=Kq_{(Na+)}q_{(Cl-)[\frac{1}{{r_{f}}} -\frac{1}{{r_{i}}}]$

Given that ri= 1.1nm= $1.1x10^{-9}m$ and rf= infinite distance

$W=(9x10^{9})(1.6x10^{-19})(-1.6x10^{-19})[\frac{1}{\alpha }-\frac{1}{(1.1x10^{-9})}]=2.1x10^{-19}J$

6 0

3 years ago

For the reaction COCl2(g)⇌CO(g)+Cl2(g), K= 2.19×10−10 at 373 K

vladimir1956 [14]

Answer:

D) The equilibrium lies far to the left

Explanation:

According to the law of mass action, the equilibrium constant K for the reaction at 373K can be calculated as follows:

K = $\frac{[CO][Cl_{2}]}{[COCl_{2}]}$ = 2.19×10^{-10}

([X] means = concentration of X)

This means that in the equilibrium the concentration of the reactant (that is in the denominator) will be much higher (around 10^{10} fold) than the concentrations of the products (that are in the numerator), and this means that the equilibrium lies far to the left (to the reactants side) as very small amount of product is being formed.

6 0

2 years ago

2. Which of the following does not have a nucleus? a. prokaryotes b. eukaryotes c. prokaryotes and eukaryotes

qwelly [4]

Answer:

Erythrocytes

Erythrocytes do not contain a nucleus. This would make answer choice "A" correct. Erythrocytes are red blood cells and these cells differ from the other cells of the body because of the absence of the nucleus. All the other cells noted have nuclei.

Explanation:

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3 0

3 years ago

Read 2 more answers

Which arrangement of electrons is correct? Help please its timed!!!

postnew [5]

Answer:

Explanation:

According to all the principles of filling it is d

8 0

2 years ago