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Sever21 [200]
3 years ago
10

What is the concentration of 60 mL of H3PO4 if it is neutralized by 225 mL of 2 M Ba(OH)2?

Chemistry
2 answers:
goldfiish [28.3K]3 years ago
8 0

7.5 M is the concentration of 60 ml of H3PO4 if it is neutralized by 225 ml of 2 M Ba(OH)2.

Explanation:

Data given:

volume of phosphoric acid, Vacid =60 ml

volume of barium hydroxide, Vbase = 225 ml

molarity of barium hydroxide, Mbase = 2M

Molarity of phosphoric acid, Macid =?

the formula for titration is used as:

Macid x Vacid = Mbase x Vbase

rearranging the equation to get Macid

Macid = \frac{Mbase x Vbase}{Vacid}

Macid =\frac{225 X 2}{60}

Macid = 7.5 M

the concentration of the phosphoric acid is 7.5 M and the volume is 60 ml. Thus 7.5 M solution of phosphoric acid is used to neutralize the barium hydroxide solution of 2M.

notka56 [123]3 years ago
5 0

Answer:

= 5 M

Explanation:

2H3PO4 + 3Ba(OH)2 ----> Ba3(PO4)2 + 3H2O

moles Ba(OH)2 = molarity x litres

= 2 M x 0.225 L

= 0.45 mol

3 moles Ba(OH)2 react with 2 moles H2SO4

So moles H2SO4 = 2/3 x moles Ba(OH)2

= 0.3 mol

molarity = moles / litres

= 0.3 mol / 0.06 L

=5M

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A rigid tank contains 1.40 moles of an ideal gas. Determine the number of moles of gas that must be withdrawn from the tank to l
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Answer : The final number of moles of gas that withdrawn from the tank to lower the pressure of the gas must be, 0.301 mol.

Explanation :

As we know that:

PV=nRT

At constant volume and temperature of gas, the pressure will be directly proportional to the number of moles of gas.

The relation between  pressure and number of moles of gas will be:

\frac{P_1}{P_2}=\frac{n_1}{n_2}

where,

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P_2 = final pressure of gas = 5.30 atm

n_1 = initial number of moles of gas = 1.40 moles

n_2 = final number of moles of gas = ?

Now put all the given values in the above expression, we get:

\frac{24.5atm}{5.30atm}=\frac{1.40mol}{n_2}

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Explanation:

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