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taurus [48]
3 years ago
11

100 points if you answer thisA B and C please people​

Chemistry
1 answer:
Naddik [55]3 years ago
7 0

Answer:

what is the product of the reaction?

What does it form?

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How would the freezing point of seawater compare with that of pure water?
astraxan [27]
Freezing Point of Sea water would be lower than that of Pure Water. It is because of salinity of the water

Hope this helps!
6 0
3 years ago
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Which of these is an example of food engineering?
Andrej [43]

Answer:

a.labeling food with an ingredient list to inform consumers

Explanation:

3 0
3 years ago
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unit that contains two or more atoms covalently bonded together but that has an overall charge is called a(n) _____ ion. Many __
OverLord2011 [107]

Answer:

polyatomic, ionic

Explanation:

unit that contains two or more atoms covalently bonded together but that has an overall charge is called a(n) polyatomic ion. Many ionic compounds contain such units.

3 0
2 years ago
A solution was prepared by mixing 50.0 g
frez [133]

Answer:

4.78 %.

Explanation:

<em>mass percent is the ratio of the mass of the solute to the mass of the solution multiplied by 100.</em>

<em></em>

<em>mass % = (mass of solute/mass of solution) x 100.</em>

<em></em>

mass of MgSO₄ = 50.0 g,

mass of water = d.V = (0.997 g/mL)(1000.0 mL) = 997.0 g.

mass of the solution = mass of water + mass of MgSO₄ = 997.0 g + 50.0 g = 1047.0 g.

<em>∴ mass % = (mass of solute/mass of solution) x 100</em> = (50.0 g/1047.0 g) x 100 = <em>4.776 % ≅ 4.78 %.</em>

4 0
4 years ago
When a 120 g sample of aluminum absorbs 9612 of heat energy, its temperature increases from 25°C to 115°C. Find the specific hea
lesantik [10]
<h3>Answer:</h3>

0.89 J/g°C

<h3>Explanation:</h3>

Concept tested: Quantity of heat

We are given;

  • Mass of the aluminium sample is 120 g
  • Quantity of heat absorbed by aluminium sample is 9612 g
  • Change in temperature, ΔT = 115°C - 25°C

                                                      = 90°C

We are required to calculate the specific heat capacity;

  • We need to know that the quantity of heat absorbed is calculated by the product of mass, specific heat capacity and change in temperature.

That is;

Q = m × c × ΔT

  • Therefore, rearranging the formula we can calculate the specific heat capacity of Aluminium.

Specific heat capacity, c = Q ÷ mΔT

                                         = 9612 J ÷ (120 g × 90°C)

                                         = 0.89 J/g°C

Therefore, the specific heat capacity of Aluminium is  0.89 J/g°C

4 0
3 years ago
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