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taurus [48]
3 years ago
11

100 points if you answer thisA B and C please people​

Chemistry
1 answer:
Naddik [55]3 years ago
7 0

Answer:

what is the product of the reaction?

What does it form?

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Read the two statements given below. Statement 1: All living matter at the smallest level is made of cells Statement 2: New anim
9966 [12]

Answer:

Statement 1: All living matter at the smallest level is made of cells

Explamation:

All living things are made of cells; the cell itself is the smallest fundamental unit of structure and function in living organisms.

Hope this helps

7 0
3 years ago
Show me step by step solution
Cloud [144]
Ok I may be young but combine the two reactions to create a compund
7 0
3 years ago
Does anyone have any idea what this means lol
miv72 [106K]

Answer:

29.42 Litres

Explanation:

The general/ideal gas equation is used to solve this question as follows:

PV = nRT

Where;

P = pressure (atm)

V = volume (L)

n = number of moles (mol)

R = gas law constant (0.0821 Latm/molK)

T = temperature (K

According to the information provided in this question;

mass of nitrogen gas (N2) = 25g

Pressure = 0.785 atm

Temperature = 315K

Volume = ?

To calculate the number of moles (n) of N2, we use:

mole = mass/molar mass

Molar mass of N2 = 14(2) = 28g/mol

mole = 25/28

mole = 0.893mol

Using PV = nRT

V = nRT/P

V = (0.893 × 0.0821 × 315) ÷ 0.785

V = 23.09 ÷ 0.785

V = 29.42 Litres

6 0
3 years ago
What is the number placed in front of a compound to balance a chemical reaction?
stiks02 [169]

coefficient: they balance the chemical equation you have to make sure the number is as small as it can. It is also used to convert different compounds to compounds or quantities to quantities.

5 0
3 years ago
Q2.  0.254 g of KHP (204 g/mol) titrated against 20.0 mL of unknown NaOH (40.0 g/mol) solution to get the end point of phenolpht
Vera_Pavlovna [14]

Answer:

<u>Mass concentration (g/L) </u><u><em>= 2.49g/L.</em></u>

Explanation:

No. of moles = \frac{mass}{molar mass}

= \frac{0.254}{204} = 0.001245 moles

Concentration of KHP (C1) in litres = n/v

= \frac{0.001245}{0.02} = 0.062 mol/L

We know that:

C_{1} V_{1} = C_{2} V_{2}

where c1v1 and c2v2 are the products of concentration and volumes of KHP and NaOH respectively.

Since mole ratio is 1 : 1.

1 mole of NaOH - 40g

0.001245 mole of NaOH = 40 × 0.001245 = 0.0498g

⇒0.0498g of NaOH was used during the titration

<u><em>∴Mass concentration (g/L) = 0.0498g ÷ 0.02L</em></u>

<u><em>= 2.49g/L.</em></u>

3 0
3 years ago
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