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Bas_tet [7]
3 years ago
15

Explain hybridization and what effects does hybridization have on bonds

Chemistry
1 answer:
Gekata [30.6K]3 years ago
5 0
Hybridization is the idea that atomic orbitals fuse to form newly hybridized orbitals, which in turn, influence molecular geometry and bonding properties.
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Raising the temperature of 10.0 g of water from 10.0 °C to 20.0 °C requires 100.0 cal of energy, while raising the temperature o
djyliett [7]

Answer:

Explanation:

The change in enthalpy of a substance when heated is given by

ΔH = m x Csp x ΔT

so the enthalpy change is dependent on the specific heat , i.e its capactity to absorb heat, and is not influenced by factors such as being closer to the melting point, volume , potential energy or being a solid or liquid.

6 0
2 years ago
When 0.100 mol of carbon is burned in a closed vessel with8.00
antoniya [11.8K]

Answer : The mass of carbon monoxide form can be 2.8 grams.

Solution : Given,

Moles of C = 0.100 mole

Mass of O_2 = 8.00 g

Molar mass of O_2 = 32 g/mole

Molar mass of CO = 28 g/mole

First we have to calculate the moles of O_2.

\text{ Moles of }O_2=\frac{\text{ Mass of }O_2}{\text{ Molar mass of }O_2}=\frac{8g}{32g/mole}=0.25moles

Now we have to calculate the limiting and excess reagent.

The balanced chemical reaction is,

2C+O_2\rightarrow 2CO

From the balanced reaction we conclude that

As, 2 mole of C react with 1 mole of O_2

So, 0.1 moles of C react with \frac{0.1}{2}=0.05 moles of O_2

From this we conclude that, O_2 is an excess reagent because the given moles are greater than the required moles and C is a limiting reagent and it limits the formation of product.

Now we have to calculate the moles of CO

From the reaction, we conclude that

As, 2 mole of C react to give 2 mole of CO

So, 0.1 moles of C react to give 0.1 moles of CO

Now we have to calculate the mass of CO

\text{ Mass of }CO=\text{ Moles of }CO\times \text{ Molar mass of }CO

\text{ Mass of }CO=(0.1moles)\times (28g/mole)=2.8g

Therefore, the mass of carbon monoxide form can be 2.8 grams.

5 0
3 years ago
What is the molarity of a solution that contains 87.75g of NaCI in 500.ml of solution
Brut [27]

Answer:

M = 3.0 mol/L.

Explanation:

  • We can calculate the molarity of a solution using the relation:

<em>M = (mass x 1000) / (molar mass x V)</em>

  • M is the molarity "number of moles of solute per 1.0 L of the solution.
  • mass is the mass of the solute (g) (m = 87.75 g of NaCl).
  • molar mass of NaCl = 58.44 g/mol.
  • V is the volume of the solution (ml) (V = 500.0 ml).

∴ M = (mass x 1000) / (molar mass x V) = (87.75 g x 1000) / (58.44 g/mol x 500.0 ml) = 3.0 mol/L.

6 0
3 years ago
Help meeeeeeeeeeeee its impossibleeeeee
fredd [130]

Answer:

Nice! If only....

Explanation:

6 0
2 years ago
Read 2 more answers
Explique las diferencias entre mezcla y combinación. De un ejemplo de cada uno.
Brums [2.3K]

Answer:

He means Explain the differences between mix and match. Give one example of each.

Explanation:

3 0
2 years ago
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