Answer:
Nickel(III) oxide is the chemical name of the compound represented by the formula Ni2O3?
C. 6, 1, 0, -1/2
Explanation:
The four quantum numbers are:
- Principal quantum number (n): this represents the energy level in which an orbital is located.
- Azimuthal quantum number gives the shape of the orbitals in subshells accommodating the electrons.
- Magnetic quantum number gives the number of spatial orientations or degeneracy of the orbitals in the subshells.
- Spin quantum number describes the spinning of an electron in either clockwise or anticlockwise directions.
To know the electron with the highest energy, we use the principal quantum number values.
n values takes whole numbers i.e n = 1,2,3,4,5,6,7.............
The higher the value, the higher the energy level.
From the given quantum numbers, C has the highest energy levels.
Learn more;
Quantum numbers brainly.com/question/9288609
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Answer:Any change that occurs without altering the chemical composition of a substance is a physical change. Physical changes can include changing the color, shape, state of matter, or volume of a substance. It is crucial to remember that physical changes never alter the chemical makeup.
Explanation:
i hope that helps u try to figure it out a little bit sorry i couldn't find your answer i didn't have much to go off of
Answer:
Explanation:
Heat required to convert ice to ice at 0⁰C
= mass x specific heat x rise in temperature
= 18 x 2.09 x 20
= 752.4 J .
heat required to convert ice at 0⁰C to water at 0⁰C
mass x latent heat of fusion
= 18 x 336
= 6048 J
Heat required to increase the temperature of water to 100⁰C
= 18 x 4.2 x 100
= 7560 J
Total heat required
7560 + 6048 + 752.4
= 14360.4 J
Answer: Li is the reducing agentg and O is the oxidizing agent.
Explanation:
1) The oxidizing agent is the one that is reduced and the reducing agent is the one that is oxidized.
2) The given reaction is:
4Li(s) + O₂ (g) → 2 Li₂O(s)
3) Determine the oxidation states of each atom:
Li(s): oxidation state = 0 (since it is alone)
O₂ (g): oxidation state = 0 (since it is alone)
Li in Li₂O (s) +1
O in Li₂O -2
That because 2× (+1) - 2 = 0.
4) Determine the changes:
Li went from 0 to + 1, therefore it got oxidized and it is the reducing agent.
O went from 0 to - 2, therefore it got reduced and it is the oxidizing agent.
