All categories

4 years ago

Hich statement describes the process of fusion, but not the process of fission?

Chemistry

1 answer:

lesantik [10]4 years ago

4 0

The answer is A. this process is only in the research phase

The process of fusion involves merging of atomic nuclei to form heavier nuclei resulting in the release of enormous amounts of energy. Fusion takes place when two low mass isotopes, typically isotopes of hydrogen, unite under conditions of extreme pressure and temperature. Scientists continue to work on controlling nuclear fusion in an effort to make a fusion reactor to produce electricity. However, progress is slow due to challenges with understanding how to control the reaction in a contained space.

You might be interested in

35.5 moles of lithium fluoride is dissolved in 65 L of solution

kkurt [141]

Answer:

Explanation:

1.10

of solution

Explanation:

The Molarity

is calculated by the equation comparing moles of solute to liters of solution

For this question we are given the Molarity 0.88M

We are told the solute is a 25.2 gram sample of LiF, Lithium Fluoride

We can convert the mass of LiF to moles by dividing by the molar mass of LiF

Li = 6.94

F = 19.0

LiF = 25.94 g/mole

25.2

25.94

0.97

moles

Now we can take the the molarity and the moles and calculate the Liters of solution

0.97

0.88

1.10

of solution i just did look at my papaer

3 0

4 years ago

The equilibrium constant, Kc, for the following reaction is 0.967 at 650 K. 2NH3(g) N2(g) 3H2(g) When a sufficiently large sampl

AlekseyPX

Answer: Concentration of $NH_3$ in the equilibrium mixture is 0.31 M

Explanation:

Equilibrium concentration of $H_2$ = 0.729 M

The given balanced equilibrium reaction is,

$2NH_3(g)\rightleftharpoons N_2(g)+3H_2(g)$

Initial conc. x 0 0

At eqm. conc. (x-2y) M (y) M (3y) M

The expression for equilibrium constant for this reaction will be:

3y = 0.729 M

y = 0.243 M

$K_c=\frac{[y]\times [3y]^3}{[x-2y]^2}$

Now put all the given values in this expression, we get :

$K_c=\frac{0.243\times (0.729)^3}{(x-2\times 0.243)^2}$

$0.967=\frac{0.243\times (0.729)^3}{(x-2\times 0.243)^2}$

$x=0.80$

concentration of $NH_3$ in the equilibrium mixture = $0.80-2\times 0.243=0.31$

Thus concentration of $NH_3$ in the equilibrium mixture is 0.31 M

3 0

3 years ago

How does adding an atom affect the position of existing atoms or lone pairs?

Paha777 [63]

Adding an atom will increase the repulsion between existing atoms and lone pairs. Added atom will result in bond pair-bond pair and bond pair-lone pair repulsion. The magnitude of the lone pair-bond pair repulsion is greater than the bond pair-bond pair repulsion. The added atom will change the electron geometry and bring about a distortion in the molecular geometry.

8 0

3 years ago

Read 2 more answers

What salt is produced in each of the following neutralization reactions? HNO3(aq)+KOH(aq)→H2O(l)+? HNO3(aq)+Ca(OH)2(aq)→H2O(l)+?

Igoryamba

Answer:

1. KNO3

2. Ca(NO3)2

3. CaCl2

4. KCl

Explanation:

In each of the neutralization reactions, the H from one of the reactant(acid) will combine with the OH from the other reactant (base) to form water while the other elements combine to give the salt as shown below:

1. HNO3 + KOH → H2O + KNO3

The salt produced is KNO3

2. 2HNO3 + Ca(OH)2 → 2H2O + Ca(NO3)2

The salt produced is Ca(NO3)2

3. 2HCl +Ca(OH)2 → 2H2O + CaCl2

The salt produced is CaCl2

4. HCl +KOH → H2O + KCl

The salt produced is KCl

5 0

3 years ago

The volume of 5.00 M KBr needed to have 1.00 mol KBr mL

astra-53 [7]

Answer: molarity = mole solute/ liter of solution.

=> volume= mole/molarity = 1/5 = 0.2 L = 200mL

Explanation:

7 0

3 years ago