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svp [43]
4 years ago
15

1. What type of reaction is listed below? Prove that it is balanced by listing the number of elements on both side of the equati

on (reactants vs. products)? CH3COOH + NaHCO3  NaCH3COO + H2CO3
Chemistry
2 answers:
ohaa [14]4 years ago
6 0
Is there a mistake or am i doing something wrong  
maria [59]4 years ago
5 0
<span>It is a double replacement, followed by a decomposition.

NaHCO3(aq) + CH3COOH(aq) → CH3COONa(aq) + H2CO3(aq) (double replacement)
H2CO3(aq) → H2O(l) + CO2(g) (decomposition)

The decomposition is so fast that you have no measurable concentration of H2CO3 in the solution. The formation of CO2 forms the bubbles in the solution. </span>
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Worth 15 points!!! Choose ALL of the examples of a heterogeneous mixture, where the components are unevenly spread. THIS IS A MU
ycow [4]

Answer:

A

B

C

Explanation:

A B and C are heterogeneous because they don’t have all the same components throughout. D is homogeneous because kool aid dissolves into the water.

5 0
3 years ago
Consider the reaction between acetylene, c2h2, and oxygen in a welding torch: 2c2h2(g) + 5o2(g) → 4co2(g) + 2h2o(g) if 5.4 moles
fredd [130]
<span>                                      2C2H2(g) + 5O2(g) → 4CO2(g) + 2H2O(g)
   from the reaction     2 mol                              4 mol
from the problem      5.4 mol                         10.8 mol

M(CO2) = 12.0 +2*16.0 = 44.0 g/mol
10.8 mol CO2 * 44.0 g CO2/1 mol CO2 = 475.2 g CO2 </span>≈480 = 4.8 * 10² g
Answer is  C. 4.8*10² g.
4 0
3 years ago
Read 2 more answers
Platinum crystallizes with the face-centered cubic unit cell. The radius of a platinum atom is 139 pm. Calculate the edge length
horrorfan [7]

Answer:

Length = 393pm, Density = 21.3 g/cm^3.

Explanation:

From the question above, we have the following parameters or data which is going to aid in solving the above Question.

=> The radius of a platinum atom = 139 pm.

Therefore, the length can be calculated by making use of the formula given below:

Length = 2 √( 2r) = 2 × √ (2 × 139 × 10^-12m ) = 393 × 10^-10 m = 393pm.

The density can be calculated by making use of the chemical formula given below:

Density = mass ÷ volume = (195.064/ 6.02 × 10^23) ÷ (3.93 × 10^-10/ 10^-2) = 21.3 g/cm^3.

3 0
3 years ago
How to calculate the number of moles
babunello [35]

Answer:

1. The formula for the number of moles formula is expressed as.

2. Given.

3. Number of moles formula is.

4. Number of moles = Mass of substance / Mass of one mole.

5. Number of moles = 95 / 86.94.

6 0
3 years ago
A piece of solid carbon dioxide with a mass of 5.50 grams is placed in a 10 Liter vessel that already contains 705 torr at 24 Ce
alex41 [277]

total pressure = ( 705 torr + 231.525torr)  =   936.525torr

7 0
3 years ago
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