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marysya [2.9K]
3 years ago
12

A compound differs from a mixture in that a compound always has a?

Chemistry
2 answers:
Rus_ich [418]3 years ago
6 0

Answer : Option 1) Homogeneous composition.

Explanation : A compound that differs from a mixture in that a compound is always has a homogeneous composition.

As separation of mixture can be done by any of the physical methods,, but a compound needs a chemical methods to be separated as it is homogeneous in composition. The components of a compound are formed by reacting chemically with each other, whereas in mixture they are just mixed together.


MissTica3 years ago
3 0
1 is the answer because I studied science it's right number 1 is the correct one homogeneous composition
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How can we reduce the production of harmful gases that form acid rain
oksano4ka [1.4K]

Answer:

A great way to reduce acid rain is to produce energy without using fossil fuels. Instead, people can use renewable energy sources, such as solar and wind power. Renewable energy sources help reduce acid rain because they produce much less pollution.

7 0
3 years ago
How many atoms are in 6.30 moles of sulfur (S)?
STatiana [176]

Answer: 3.79*10^24 atoms

Explanation:

1 mole = 6.02214076*10^23 atoms

8 0
3 years ago
If you initially have a volume of 4 L and a temperature of 300K. Then you decreased the volume to 2 L, what is the new temperatu
ASHA 777 [7]

Answer:

T₂ = 150 K

Explanation:

Given data:

Initial volume = 4 L

Initial temperature = 300 K

Final volume = 2 L

Final temperature = ?

Solution:

The given problem will be solve through the Charles Law.

According to this law, The volume of given amount of a gas is directly proportional to its temperature at constant number of moles and pressure.

Mathematical expression:

V₁/T₁ = V₂/T₂

V₁ = Initial volume

T₁ = Initial temperature

V₂ = Final volume  

T₂ = Final temperature

Now we will put the values in formula.

V₁/T₁ = V₂/T₂

T₂ = T₁V₂/V₁  

T₂ = 300 K × 2L / 4 L

T₂ = 600 L.K / 4 L

T₂ = 150 K

3 0
3 years ago
Suppose a 0.025M aqueous solution of sulfuric acid (H2SO4) is prepared. Calculate the equilibrium molarity of SO4−2. You'll find
FromTheMoon [43]

<u>Answer:</u> The concentration of SO_4^{2-} at equilibrium is 0.00608 M

<u>Explanation:</u>

As, sulfuric acid is a strong acid. So, its first dissociation will easily be done as the first dissociation constant is higher than the second dissociation constant.

In the second dissociation, the ions will remain in equilibrium.

We are given:

Concentration of sulfuric acid = 0.025 M

Equation for the first dissociation of sulfuric acid:

       H_2SO_4(aq.)\rightarrow H^+(aq.)+HSO_4^-(aq.)

            0.025          0.025       0.025

Equation for the second dissociation of sulfuric acid:

                    HSO_4^-(aq.)\rightarrow H^+(aq.)+SO_4^{2-}(aq.)

<u>Initial:</u>            0.025            0.025      

<u>At eqllm:</u>      0.025-x          0.025+x        x

The expression of second equilibrium constant equation follows:

Ka_2=\frac{[H^+][SO_4^{2-}]}{[HSO_4^-]}

We know that:

Ka_2\text{ for }H_2SO_4=0.01

Putting values in above equation, we get:

0.01=\frac{(0.025+x)\times x}{(0.025-x)}\\\\x=-0.0411,0.00608

Neglecting the negative value of 'x', because concentration cannot be negative.

So, equilibrium concentration of sulfate ion = x = 0.00608 M

Hence, the concentration of SO_4^{2-} at equilibrium is 0.00608 M

4 0
3 years ago
One quarter of a 1-mole piece of iron turns to rust in six months. Which rate describes the speed at which the iron rusts?
avanturin [10]
1/4 mol = 0.25 mol

6 months = 0.5 year

rate = 0,25 mol / 0.5 year = 0.5 mol/year or approx 0.042 mol/month
7 0
3 years ago
Read 2 more answers
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