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Katyanochek1 [597]
2 years ago
12

The rotating blade of a blender turns with constant angular acceleration of 1.51 rad/s^2. How much time does it take to reach an

angular velocity of 36.8 rad/s, starting from rest?
Physics
1 answer:
yawa3891 [41]2 years ago
6 0

time to reach an angular velocity of 36.8 is 24.370 s.

<h3></h3><h3>What is angular acceleration?</h3>

The temporal rate at which angular velocity changes is referred to as angular acceleration. Naturally, there are two forms of angular acceleration, referred to as spin angular acceleration and orbital angular acceleration, just as there are two types of angular velocity, namely spin angular velocity and orbital angular velocity. As opposed to orbital angular acceleration, which is the angular acceleration of a point particle around a fixed origin, spin angular acceleration describes the angular acceleration of a rigid body about its centre of rotation.

w(t) = w(0) + α*t

also w(0) =0

=> time = 36.8/1.51= 24.370 s

to learn more about angular acceleration go to - brainly.com/question/21278452

#SPJ4

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A uniform meter rule with a mass of 200g is suspended at zero mark pivotes at 22.0cm mark. calculate the mass of the rule.
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Answer:

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Explanation:

Given;

mass of the object suspended at zero mark, m₁ = 200 g

pivot of the uniform meter rule = 22 cm

Total length of meter rule = 100 cm

0                          22cm                                  100cm

-------------------------Δ------------------------------------

↓                                                                       ↓

200g                                                                 m₂  

Apply principle of moment

(200 g)(22 cm - 0)     = m₂(100 cm - 22 cm)

(200 g)(22 cm) = m₂(78 cm)

m₂ =  (200 g)(22 cm)  / (78 cm)

m₂ = 56.41 g  

Therefore,  the mass of the rule is 56.41 g                                            

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Below is an attachment containing the solution.

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