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3 years ago

(5.8 x 10) - (2.2 x 105)

Mathematics

2 answers:

3241004551 [841]3 years ago

6 0

The answer you're looking for is -173

Nadusha1986 [10]3 years ago

6 0

-173 is the answer to that hope i helped!

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If Janis and Melanie make bracelets one afternoon during Choice time. They make six bracelets each. They feel generous and give

dusya [7]

3 each left. Hope it helped

5 0

3 years ago

What is the simplest form of 54/54

krek1111 [17]

1 is the simplest form since the line means division. 54 divided by 54 is 1.

4 0

3 years ago

Read 2 more answers

Julio is paid 1.4 times his normal hourly rate for each hour he works over 32 hours in a week. Last week he worked 43 hours and

nekit [7.7K]

Answer:

$r = \$14.71$

Step-by-step explanation:

Given

Normal Hour = 32 hours

Overtime = Hours above 32

Rate for Overtime = 1.4 times normal rate

Earnings = $535.62

Required

Determine the normal hour pay

First, we need to determine the hours worked overtime.

This is:

$Overtime = 43 - 32$

$Overtime = 11$

The equation that binds all the parameters is:

$Earnings = Normal\ Hour * Normal\ Rate + Overtime * Overtime\ Rate$

This gives:

$535.62 = 21 * r + 11 * 1.4r$

$535.62 = 21r + 15.4r$

$535.62 = 36.4r$

Solve for r

$r = 535.62/36.4$

$r = \$14.71$

4 0

3 years ago

Micheal has been awarded a pay rise of 4%.His salary is £ 24 492 <br> What was his apart before?

Nesterboy [21]

Because there was a pay rise, we can write the equation as x+0.04x = 24.492 and solve for x.

x+0.04x = 24.492
1.04x = 24.492
x=23.55

His original pay was £23.55

6 0

3 years ago

i need help with this equation please there are two more possible answers that were cut off they are 17,2% and 19,5%

Margarita [4]

Consider that the experimental probability of an event is based upon the previous trials and observations of the experiment.

The experimental probability of occurrence of an event is given by,

$\text{Probability of an event}=\frac{\text{ Number of outcomes that favoured the event}}{\text{ Total number of trials or outcomes}}$

As per the problem, there are a total of 1230 trials of rolling a dice.

And the favourable event is getting a 2.

The corresponding experimental probability is calculated as,

$\begin{gathered} P(\text{ getting a 2})=\frac{\text{ No. of times 2 occurred}}{\text{ Total no. of times the dice is thrown}} \\ P(\text{ getting a 2})=\frac{172}{1230} \\ P(\text{ getting a 2})\approx0.13984 \\ P(\text{ getting a 2})\approx13.98\text{ percent} \end{gathered}$

Thus, the required probability is 13.98% approximately.

Theref

7 0

1 year ago