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avanturin [10]
3 years ago
8

How many moles of water will be produced when 15.0 g of calcium chloride dihydrate are heated ?

Chemistry
1 answer:
Vanyuwa [196]3 years ago
4 0

Answer:

0.204 mol

Explanation:

Step 1: Write the balanced equation for the heating of calcium chloride dihydrate

CaCl₂.2H₂O ⇒ CaCl₂ + 2H₂O

Step 2: Calculate the moles of calcium chloride dihydrate

The<em> molar mass of CaCl₂.2H₂O</em> is 147.01 g/mol. The moles corresponding to 15.0 g of CaCl₂.2H₂O are:

15.0g \times \frac{1mol}{147.01g} = 0.102 mol

Step 3: Establish the molar ratio of CaCl₂.2H₂O to H₂O

According to <em>the balanced equation</em>, the molar ratio of CaCl₂.2H₂O to H₂O is 1:2.

Step 4: Use the molar ratio to calculate the moles of water produced from 0.102 moles of calcium chloride dihydrate

0.102molCaCl_2.2H_2O \times \frac{2molH_2O}{1molCaCl_2.2H_2O} = 0.204molH_2O

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How many molecules of sodium oxide will be created if 187 grams of oxygen reacts with excess sodium? 4na o2 -&gt; 2na2o
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Molecules of sodium oxide will be created if 187 grams of oxygen reacts with excess sodium will be 7.04 × 10 ²⁴ molecules.

Sodium oxide is Na₂O which is formed due to the reaction of sodium and oxygen.

Given,

Balanced chemical equation is :

         4 Na(s) + O₂ (g) → 2Na₂O (s)

Now, the Mole ratio of O₂ and Na₂O is 1 mol O₂: 2 mol Na₂O

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Number of moles of O₂ = 187 g / 32.00 g/mol

Number of moles of O₂ = 5.844 mol

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x = 5.844 mol O₂ (2 mol Na₂O / 1 mol O₂)

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Learn more about Sodium oxide here,

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2 years ago
The boiling point of an aqueous 1.83 m (nh4)2so4 (molar mass = 132.15 g/mol) solution is 102.5°c. determine the value of the van
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We need to know the value of van't hoff factor.

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(NH₄)₂SO₄ is an ionic compound, so it dissociates in solution and produces 3 ionic species. Therefore van't hoff factor is more than one.

From the equation: ΔT_{b}=i K_{b}.m, where ΔT_{b}= elevation of boiling point=102.5 - 100=2.5°C.

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