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avanturin [10]
3 years ago
8

How many moles of water will be produced when 15.0 g of calcium chloride dihydrate are heated ?

Chemistry
1 answer:
Vanyuwa [196]3 years ago
4 0

Answer:

0.204 mol

Explanation:

Step 1: Write the balanced equation for the heating of calcium chloride dihydrate

CaCl₂.2H₂O ⇒ CaCl₂ + 2H₂O

Step 2: Calculate the moles of calcium chloride dihydrate

The<em> molar mass of CaCl₂.2H₂O</em> is 147.01 g/mol. The moles corresponding to 15.0 g of CaCl₂.2H₂O are:

15.0g \times \frac{1mol}{147.01g} = 0.102 mol

Step 3: Establish the molar ratio of CaCl₂.2H₂O to H₂O

According to <em>the balanced equation</em>, the molar ratio of CaCl₂.2H₂O to H₂O is 1:2.

Step 4: Use the molar ratio to calculate the moles of water produced from 0.102 moles of calcium chloride dihydrate

0.102molCaCl_2.2H_2O \times \frac{2molH_2O}{1molCaCl_2.2H_2O} = 0.204molH_2O

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Explanation:

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From this, we find that the relation between HNO3 and Ca(OH)2 is that 2 moles of HNO3 react with 1 mole of Ca(OH)2.

2nd) This is the order of the relations that we have to use in the equation to calculate the grams of nitric acid:

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,

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,

• relation of the 2 moles of HNO3 that react with 1 mole of Ca(OH)2 .

,

• using the molar mass of HNO3 (63.02g/mol).

4.30g\text{ Ca\lparen OH\rparen}_2*\frac{1\text{ mol Ca\lparen OH\rparen}_2}{74g\text{ Ca\lparen OH\rparen}_2}*\frac{2\text{ moles HNO}_3}{1\text{ mole Ca\lparen OH\rparen}_2}*\frac{63.02g\text{ HNO}_3}{1\text{ mole HNO}_3}=7.32g\text{ HNO}_3

So, 7.32g of HNO3 are required.

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