4y ≥ 3x + 2
Plugging in the values in the options, then the required values are when x = 6 and y = 5, then
4(5) ≥ 3(6) + 2
20 ≥ 18 + 2
20 ≥ 20
Answer:
312π mm³
Step-by-step explanation:
Given:
Oblique cone height, h = 14 mm
radius of half sphere = base radius of cone, r = 6 mm
Recall the volume of 1/2 - sphere
= 1/2 x volume of sphere
= 1/2 x (4π/3) r³
= 1/2 x (4π/3) (6)³
= 144π
Also volume of an oblique cone =
=volume of a right cone
= (π/3) r²h
= (π/3) 6²(14)
=168π
Volume of composite figure = 144π + 168π = 312π mm³
is this the full question?
The answer is 1/2. Multiply 3/4 by 2/3.
83 1/3 % = 5/6 so
20 = (5/6)x
x = (6/5)(20) = 24
