A species with a positive charge will have a net attraction to a species with a negative charge. Among the choices, N3- is the only one attracted to a positive charge.
Answer: The balanced equation for the given reaction is
.
Explanation:
A chemical equation which contains same number of atoms on both reactant and product side.
For example, 
Here, number of atoms on reactant side are as follows.
Number of atoms on product side are as follows.
To balance this equation, multiply 
by 2 on reactant side and multiply 
by 2. Hence, the equation will be re-written as follows.
Here, number of atoms on reactant side are as follows.
Number of atoms on product side are as follows.
Now, there are same number of atoms on both reactant and product side. So, this equation is balanced.
Thus, we can conclude that the balanced equation for the given reaction is .
The elements in<span> groups 1a through 7a are called d. representative elements. The periodic table is organized according to increasing order of the atomic number of the elements. Groups have similar properties while the period of the elements determines the valence electrons in the outer shells.</span>
Answer:5 to the 7th power
Explanation:
Divided 7 and y then add 4
Nitrogen has 7 protons, 7 neutrons, and 7 electrons.
Seven protons, seven neutrons, and seven electrons make up nitrogen-14.
Utilize the atomic number and mass number of an atom to determine the number of subatomic particles it contains: Atomic number Equals proton count. Electron count equals atomic number. Atomic number - mass number equals the number of neutrons.
Seven protons, seven neutrons, and seven electrons make up the atom of nitrogen. The nucleus is the collection of protons and neutrons that make up the center of an atom. The 7 electrons, which are much smaller than the nucleus, orbit it in what is known as orbits. Since nitrogen-14 is a neutral atom, the number of protons in its nucleus must match the number of electrons around it.
Learn more about atomic numbers at brainly.com/question/2942556
#SPJ4.
