Answer:
2.98 g CO2
Explanation:
1. Balance the chemical equation
1 Fe2O3 + 3CO -> 2Fe + 3CO2
2. Use periodic table to find mass from each CO2 and Fe2O3
3. Calculate
3.60 g Fe2O3 x x = 2.98 g CO2
2C8H18 + 25O2 ----> 16CO2 + 18H2O
<span>2 moles of octane gives 16 moles of CO2 </span>
<span>so 1 mole of octane will give = 16/2 = 8 moles of CO2 </span>
<span>so 603 moles of octane will give 8 X 603 = 4824 moles of CO2 </span>
<span>now use PV = nRT </span>
<span>P = 0.995 atm </span>
<span>V = ? L </span>
<span>n = 4824</span>
<span>R = 0.0821 L atm/K/mole </span>
<span>T = 28 + 273 = 301 K </span>
<span>0.995 X V = 4824 X 0.0821 X 301 </span>
<span>V = 4824 X 0.0821 X 301/ 0.995 = 119810.22 L</span>
Paradoxes and Russell's Type Theories.
Simple Type Theory and the λ -Calculus.
Ramified Hierarchy and Impredicative Principles.
Type Theory/Set Theory.
Type Theory/Category Theory.
Extensions of Type System, Polymorphism, Paradoxes.
Univalent Foundations.