The magnitude of the unknown height of the projectile is determined as 16.1 m.
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Magnitude of the height</h3>
The magnitude of the height of the projectile is calculated as follows;
H = u²sin²θ/2g
H = (36.6² x (sin 29)²)/(2 x 9.8)
H = 16.1 m
Thus, the magnitude of the unknown height of the projectile is determined as 16.1 m.
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Answer:
15.75 m
Explanation:
First, let's look at the top brick by itself. In order for it not to tip over the bottom brick, its center of gravity must be right at the edge of the bottom brick. So the edge of the top brick must be 10.5 m from the edge of the bottom brick.
Now let's look at both bricks as a combined mass. We know the total length of this combined brick is 10.5 m + 21 m = 31.5 m. And we know that for it to not tip over the edge of the surface, its center of gravity must be at the edge. So the edge of the combined brick must be 31.5 m / 2 = 15.75 m from the edge of the surface.
The base of the pyramid has the producers and everything else above the base falls under the consumers category i.e the locusts,frogs and the snake. The grass is the producer, the locust is a consumer, the frog is a special type of omnivore, termed the "life-history omnivore" since they eat both plants and animals but at different times in their lives. In this case they are just omnivores and lastly, the snake is a carnivore.
Atomic mass = number of protons + number of neutrons = 4+5 = 9 amu