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svet-max [94.6K]
1 year ago
10

Help me please forget about you and she was

Physics
1 answer:
ra1l [238]1 year ago
5 0

The figure is showing a volume of 2.4 mL becuase it's feel 4 little segments.

Therefore, the answer is 2.4 mL.

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What is a neoplasm? A. Another word for a malignant tumor B. A type of carcinoma that grows only in the mouth C. A benign swelli
Umnica [9.8K]
<h2>Answer: Any new and abnormal growth</h2>

A <u>neoplasm</u> is any <u>uncontrolled growth</u> of abnormal cells or tissues in the body.

This abnormal mass can be benign or malignant (carcinogenic).

Therefore, the correct option is D.

3 0
3 years ago
Can anyone plz help me ​
Alekssandra [29.7K]

Answer:

1.) volume = 8 cm^3

2.) density = 2.6 g/cm^3

Explanation:

1.) volume =

side {}^{3}

=》

{2}^{3}

=》

8 \: cm {}^{3}

2.) density =

\frac{mass}{volume}

=》

\frac{20.8}{8}

=》

2.6 \: g \: cm {}^{ - 3}

density = 2.6

3 0
3 years ago
A chain of length L has a mass of m which is uniformly distributed. When it is placed on a smooth horizontal table, 1/4 of its l
krok68 [10]

Gravitational potential energy has changed from the beginning to the chain just sliding away from the table willl be MgL/24.

<h3>What is gravitational potential energy?</h3>

The energy that an item has due to its location in a gravitational field is known as gravitational potential energy.

Length of hanging part, L/4

The gravitational potential energy is;

Work = Gravitational potential energy

Work done =force×displacement

\rm W = \frac{Mg}{3} \times \frac{L}{8} \\\\ W = \frac{MgL}{24}

Hence, gravitational potential energy has changed from the beginning to the chain just sliding away from the table willl be MgL/24.

To learn more about the gravitational potential energy, refer;

brainly.com/question/3884855

#SPJ1

6 0
2 years ago
How long does it take to get from a new moon to a first quarter moon
Andru [333]

'First Quarter' is the phase that appears one quarter of the
period of time from one new moon to the next one.

The total period of the moon's phases is 29.53 days (rounded).

One quarter of it is (29.53 / 4) =  <em>7 days  9.2 hours</em>   (rounded)


5 0
3 years ago
A Carnot engine has a power output of 148 kW. The engine operates between two reservoirs at 17◦C and 727◦C. How much thermal ene
Elanso [62]

Answer:

The thermal Energy absorbed each hour = 750420 kJ

Explanation:

Efficiency of a Carnot engine = W/Q = (Th-Tc)/Th ............... Equation 1.

W/Q = (Th-Tc)/Th

making Q the subject of the equation above,

Q = W(Th)/(Th-Tc)........................ Equation 2

Where Q = input power, W = output power, Th = temperature of the hot reservoir, Tc = Temperature of the cold reservoir.

<em>Given: W= 148 kW, Th = 727 °C = 727 + 273 = 1000 K, Tc = 17  °C =17 + 273 = 290 K.</em>

<em>Substituting these values into equation 2,</em>

<em>Q = 148(1000)/(1000-290)</em>

<em>Q = 148000/710</em>

Q = 208.45 kw

The thermal Energy absorbed each hour = 208.45 kW × 3600 s

The thermal Energy absorbed each hour = 750420 kJ

3 0
3 years ago
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