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1 year ago

Help me please forget about you and she was

Physics

1 answer:

ra1l [238]1 year ago

5 0

The figure is showing a volume of 2.4 mL becuase it's feel 4 little segments.

Therefore, the answer is 2.4 mL.

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A spring stores potential energy U0 when it is compressed a distance x0 from its uncompressed length.

beks73 [17]

Answer:

Explanation:

Using Hooke's law

Elastic potential energy = 1/2 K x²

K is elastic constant of the spring

x is the extension of the spring

a) The elastic potential energy when the spring is compressed twice as much Uel = 1/2 k (2x₀) ² = 4 (1/2 kx₀²)= 4 U₀

b) when is compressed half as much Uel = 1/2 k $\frac{x0}{4} ^{2}$ = $\frac{1}{4}$ ( U₀)

c) make x₀ subject of the formula in the equation for elastic potential

x₀ = $\sqrt{\frac{2U0}{K} }$

x, the amount it will compressed to tore twice as much energy = $\sqrt{\frac{2 (2U0)}{K} }$

x = √2 x₀

d) x₁, the new length it must be compressed to store half as much energy = $\sqrt{\frac{2 (\frac{1}{2})U0 }{K} }$

x₁ = $\sqrt{\frac{1}{2} }$ x₀

5 0

3 years ago

Cars are safety tested to see how quickly they come to a stop under many conditions. The distance and time of one of these tests

stepladder [879]

Answer:Is C,0

Explanation:

5 0

3 years ago

Read 2 more answers

A police car parked on the side of the highway emits a 1200 Hz sound that bounces off a vehicle farther down the highway and ret

emmasim [6.3K]

f' = frequency observed by the police car after sound reflected from the vehicle and comes back to police car = 1250 Hz

f = frequency emitted by the police car = 1200 Hz

V = speed of sound = 340 m/s

v = speed of vehicle = ?

frequency observed by the police car is given as

f' = f (V + v)/(V - v)

inserting the values in the above equation

1250 = 1200 (340 + v)/(340 - v)

v = 6.9 m/s

4 0

3 years ago

Read 2 more answers

A ball is thrown nearly vertically upward from a point near the cornice of a tall building. It just misses the cornice on the wa

vovangra [49]

Answer:

a) 48.5 ft/s

b) 36.5 ft

c) -80.3 ft/s

Explanation:

The equation of motion of the ball is :

y(t) = -16.1 ft/s^2 * t^2 + Vo*t

Where Vo is the initial velocity

If y(5s) = - 160 ft:

-160 ft = -16.1 ft/s^2 * (5 s)^2 + Vo*(5s)

Solving for Vo

Vo = (16.1*25- 160) ft / 5s = 48.5 ft/s

To answer this question we must first know when the velocity became zero, at this time is when the ball was at its highest point.

v(t) = -32.2 ft/s^2 * t + Vo

t = Vo/32.2ft/s^2 = 1.5 s

And now, the highest point which the ball reached is given by:

y(1.5s) = -16.1 ft/s^2 * (1.5)^2 + Vo*(1.5s)

y(1.5s) = 36.52 ft

We now need the time at which y(t') = -64 ft

-64 = -16.1*t'^2 + 48.5*t'

By means of the quadratic formula, we find that

t' = 4.00498 s ≈ 4 s

And the velocity at t = 4s is:

v(4s) = -32.2 ft/s^2 * 4s +48.5 ft/s = -80.3 ft/s

3 0

3 years ago

What circumstance would allow an officer to search a home even if they didn’t have a warrant?

Ipatiy [6.2K]

Answer:

Explanation:

The officer would have had permission regardless of anything else, kind of like letting someone into your house.

5 0

2 years ago