Newton's first law says that an object at rest will stay at rest, while an object in motion will stay in motion unless acted upon by an outside force.
A great example of this is a ball sitting on the ground. The ball will not move until some force is used on it, rather that be you kicking it, the wind blowing it, etc. Once that force is used against it, the ball will continue to move until gravity, air resistance, a friction bring it to a stop.
Answer:
Divergent plate margins
Explanation:
Divergent plate margins are constructive zones on the surface of the earth. They are constructive in the sense that new materials are brought to the surface from within the crust.
An example of such is the mid-altlantic ridge. Here as two plates pull apart, new melts up-wells and finds a way to get to the surface where they cool and solidify.
Answer:
the importance that the experimental and predicted values are equal is to know the validity of the models and approximations used.
Explanation:
The different models and laws of physics create perditions on the results that must be obtained under certain conditions.
To know if these models and laws are true, experiments are designed that give experimental results, which can be compared with those predicted if the models are true and accept as correct and if they are different, the moldings are reviewed and modified to be more similar to reality.
Therefore, the importance that the experimental and predicted values are equal is to know the validity of the models and approximations used.
Answer:
Density is an important physical property of matter. It reflects how closely packed the particles of matter are. When particles are packed together more tightly, matter has greater density.
Explanation:
Answer:
The energy loss due to friction is 9465 J.
Explanation:
The given data :-
Mass of roller (m) = 500 kg.
The speed of roller coaster at height 27 m = 5.6 m/s.
Initial height of roller( h ) = 27 m.
The speed of roller coaster at bottom = 22 m/s.
Initial energy of roller at a height 27 m.
E₁ = K.E + P.E
E₁ = = = 7840 + 132435
E₁ = 140,275 J
The energy of roller at a height 2 m.
E₂ = K.E + P.E
E₂ = = = 121000 + 9810
E₂ = 130,810 J
The energy loss due to friction = E₁ - E₂ = 140,275 - 130,810 = 9465 J.