Answer:
7.5 × 10^9 J.
Explanation:
So, we are given the following data or parameters or information for the proper solving of the question above;
=> ''actual force exerted by the tractor beam as a function of position is given by F(x) = ax + , where a = 6.1 x 10 N/mº and B = -4.1 x 10° N''
=> " Assume the supply spacecraft had an initial kinetic energy of KE = 2.7 x 10" J "
=> "that the tractor beam force is applied on the spacecraft over a distance of 7.5 x 10^11 m away.from its beginning position at = 0.0 m"
So, we can then solve it as;
KE2 – KE1 = F(x) dr.
KE2 - 2.7 x 10^11 J = - 3.5 × 10^6 × 7.5 x 10^4.
KE2 = 7.5 × 10^9 J.
Answer:
2.62 m
Explanation:
Let the small child sit at a distance x from the pivot.
The distance of big child from the pivot is 4 - x .
By using the concept of moments.
Clockwise moments = anticlockwise moments
27 x = 51 ( 4 - x )
27 x = 204 - 51 x
78 x = 204
x = 2.62 m
<span>There are Billions and billions of galaxies in the universe containing Trillions and trillions of stars in each galaxy.</span>
Answer:
ΔL = L0 C ΔT
We need to find C the constant of expansivity
C = ΔL / (L0 ΔT)
C = .96 / (15.04 * 65) = 9.82 * 10^-4 / deg C
