Problem 2
Answer: Choice D only
Explanation:
Let's go through the list of possible answers
- A) She only would feel a force pulling her toward the chair, hence making her feel heavier, only when the space ship is accelerating faster. In this case, she is moving a constant speed of 0.5c (aka half the speed of light). Despite going this fast, she is moving at a constant speed and therefore not accelerating at this current time. The speed isn't changing. Therefore, she would not feel a force pushing her into the chair. Choice A is off the list.
- B) This is also off the list as well. The lack of accelerating force means her lungs aren't compressed and breathing should be normal. This is assuming she doesn't have any medical conditions hindering her breathing. We can cross choice B off the list.
- C) This is similar to choice B. We can cross it off the list.
- D) The faster you go, the more time dilation will occur. This effectively compresses time and makes it slow down. The more detailed explanation involves relativity which is very complicated. Therefore, choice D is the answer.
- E) This is false because choice D was mentioned to be true.
D = vt
v = 65 km/hr
t = 180 min = 3 hrs
d = (65 km/hr)(3 hrs) = 195 km
The car was going North, so the final complete answer is 195 km North, which is choice (3).
Answer:
9.5 seconds
Explanation:
You need to make the ending speed into meters per sec.
So it would be 120km/h = 33.33m/s
If the acceleration rate is 3.5m/s, then the final answer would equal to 9.5 seconds
Also btw rounding it up is a good idea too so 10 seconds if you round
Answer:
Final velocity of the first person is 3.43m/s and that of the second person is 0.0242m/s
Explanation:
Let the momentum of the first person, the ball second person be Ma, Mb and Mc.
From the principle of the conservation of momentum, sum of the momentum before collision is equal to the sum of the momentum after collision.
Ma1 + Mb1 = Ma2 + Mb2.
The ball and the first person are both moving together with a common velocity 3.45m/s.
Let the velocity of the first person be v1
Therefore
67.5×3.45+ 0.041×3.45= 67.5v1 + 0.041×34
233.02 = 1.39+ 67.5v1
67.5v1 = 233.02 - 1.39 = 231.61
v1 = 231.61 / 67.5
v1 = 3.43m/s
The second person and the ball move together with a common velocity after catching the ball.
For the second person and the ball let their final common velocity be v
Mb2 + Mc2 = Mb3 + Mc3
0.041 × 34 + 57.5 ×0 = (57.5 + 0.041)×v
57.541v = 1.39
v = 1.39 /57.541
v = 0.0242m/s