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Sergio039 [100]
3 years ago
6

Write a short paragraph that explains how a sport using a ball would be played differently on a planet of your choice. For examp

le, how would gravity affect a basketball game on Saturn? Or how would gravity affect a baseball game on Mercury?
(Doesnt have to be a full paragraph answer I just need a gist of what it is)
Physics
1 answer:
Lynna [10]3 years ago
5 0

on a different planet I would play a sport similar to soccer. The main difference is that there is zero gravity. To win the game u have to get the ball into the other person's net first.

Explanation:

I was just bored

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Observe yourself breathing and count the number of times you inhale per second. During each breath you probably inhale 0.66 L of
Pavel [41]

To solve this exercise it is necessary to apply the concepts related to Robert Boyle's law where:

PV=nRT

Where,

P = Pressure

V = Volume

T = Temperature

n = amount of substance

R = Ideal gas constant

We start by calculating the volume of inhaled O_2 for it:

V = 21\% * 0.66L

V = 0.1386L

Our values are given as

P = 1atm

T=293K R = 0.083145kJ*mol^{-1}K^{-1}

Using the equation to find n, we have:

PV=nRT

n = \frac{PV}{RT}

n = \frac{(1)(0.1386)}{(0.0821)(293)}

n = 5.761*10^{-3}mol

Number of molecules would be found through Avogadro number, then

\#Molecules = 5.761*10^{-3}*6.022*10^{23}

\#Molecules = 3.469*10^{21} molecules

7 0
3 years ago
A force acts on a moving rubber ball.
s344n2d4d5 [400]

Answer:

B

Explanation:

because it would change the direction and speed

8 0
2 years ago
when an object is placed near a concave mirror, at what position does it forms a magnified and erect image.​
alexira [117]

Answer:

Between the principal focus and the pole of the mirror

4 0
3 years ago
Two parallel slits are illuminated with monochromatic light of wavelength 567 nm. An interference pattern is formed on a screen
iren [92.7K]

Answer:

a)1984.5nm

b)523mm

Explanation:

A)A destructive interference can be explained as when the phase shifting between the waves is analysed by the path lenght difference

θ=(m+0.5)λ where m= 1,2.3....

Where given from the question the 4th dark Fringe which will take place at m= 3

θ=7/2y

Where y= 567nm

= 7/2(567)=1984.5nm

But

B)tan θ ≈ y/d

And sinθ = mλ/d

y=mλd when m= 1 which is the first bright we have

Then y=(1× 567.D)/d

But the distance from Central to the 4th dark Fringe is 1.83cm then

y= 7λD/2d= 1.83cm

D/d=(2)×(1.83×10^-2)/(7×567×10^-9)

=92221.5

y= (567×10^-9)× (92221.5)

=0.00523m

Therefore, the distance between the first and center is y1-y0= 523mm

3 0
3 years ago
Abnormal levels of __________ may lead to Alzheimer’s disease.
IgorC [24]

Answer:

D

Explanation:

7 0
4 years ago
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