Aswer:
False, the values of the distance traveled and the displacement only coincide when the trayectorie is a straight line. Otherwise, the distance will always be greater than the offset.
Although these terms are used synonymously in other cases, they are totally different. Since the distance that a mobile travels is the equivalent of the length of its trajectory. Whereas, the displacement will be a vector magnitude.
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Answer:
wA - T =mA(a)
second option
Explanation:
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The equation of motion of a particle is given by,
s =
Let velocity of particle is denoted by v.
The velocity of the particle is given by,
velocity (v) =
v =
v =
v =
Thus, Velocity of particle is given by,
v =
Let acceleration of the particle is denoted by a.
The acceleration of particle is given by,
Acceleration =
a =
a =
a = 12t - 16
Thus, acceleration of the particle is given by,
a = 12t - 16
Answer:
303 Ω
Explanation:
Given
Represent the resistors with R1, R2 and RT
R1 = 633
RT = 205
Required
Determine R2
Since it's a parallel connection, it can be solved using.
1/Rt = 1/R1 + 1/R2
Substitute values for R1 and RT
1/205 = 1/633 + 1/R2
Collect Like Terms
1/R2 = 1/205 - 1/633
Take LCM
1/R2 = (633 - 205)/(205 * 633)
1/R2 = 428/129765
Take reciprocal of both sides
R2 = 129765/428
R2 = 303 --- approximated