Answer:
I hope this helps and I'm not to late
A way the balls behave the same way is by bouncing about 1 time after throwing the balls up. A way the balls act differently is the blue ball is bouncier than all the balls, the red ball bounces about 2 times before stopping, and the green ball doesn’t really bounce except for one time.
Explanation:
you also can use paraphrase to help you reword bye bye!!
Answer: The machine must apply the force over a shorter distance. That's because a machine doesn't change the amount of work and work equals force times distance. Therefore, if force increases, distance must decrease
FALSE
HOPE THIS HELPS
The resistance of the piece of wire is
![R= \frac{\rho L}{A}](https://tex.z-dn.net/?f=R%3D%20%5Cfrac%7B%5Crho%20L%7D%7BA%7D%20)
where
![\rho = 1.68 \cdot 10^{-8}\Omega m](https://tex.z-dn.net/?f=%5Crho%20%3D%201.68%20%5Ccdot%2010%5E%7B-8%7D%5COmega%20m)
is the resistivity of the copper
![L=5.1 cm=0.051 m](https://tex.z-dn.net/?f=L%3D5.1%20cm%3D0.051%20m)
is the length of the piece of wire
![A=0.13 cm^2 = 0.13 \cdot 10^{-4} m^2](https://tex.z-dn.net/?f=A%3D0.13%20cm%5E2%20%3D%200.13%20%5Ccdot%2010%5E%7B-4%7D%20m%5E2)
is the cross sectional area of the wire
By substituting these values, we find the value of R:
![R= \frac{\rho L}{A}=6.6 \cdot 10^{-5} \Omega](https://tex.z-dn.net/?f=R%3D%20%5Cfrac%7B%5Crho%20L%7D%7BA%7D%3D6.6%20%5Ccdot%2010%5E%7B-5%7D%20%5COmega%20%20)
Then, by using Ohm's law, we find the potential difference between the two points of the wire:
Answer:
Normal force=mg
Explanation:
The reaction force of weight is the normal force.
in order to find the normal for we need to write all the forces and set it equal to the net force:
N-mg=ma (since it is a constant speed the a=0)
N=mg