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GREYUIT [131]
3 years ago
6

Reaction rate depends on how many molecules come into contact with each other with enough energy to react. How would you increas

e the number of molecules that come in contact with each other in a reaction between gases?
A.increase volume
B.increase pressure
C.decrease pressure
D.decrease temperature
Physics
1 answer:
Pachacha [2.7K]3 years ago
4 0
A is the answer ugh i suck at physics


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A type of friction that occurs when air pushes against a moving object causing it to negatively accelerate
Romashka [77]

Answer:

Air resistance

Answer B is correct

Explanation:

The friction that occurs when air pushes against a moving object causing it to negatively accelerate is called as air resistance.

hope this helps

brainliest appreciated

good luck! have a nice day!

6 0
3 years ago
What is 7.832 rounded to the nearest 10th?
Galina-37 [17]

When rounding you look at the number right after the one you want to round. The tenth place is the one right after the decimal. If the number after it is more than five it goes up by one, it it's less than five it stays the same. So since the number after the 8 is a 3 it stays the same.

The answer is 7.8

3 0
2 years ago
A 10-N force is needed to move an object with a constant velocity of 5.0 m/s. What power must be delivered to the object by the
vagabundo [1.1K]

The power that must be delivered to the object by the force is 50 W

Power is defined as the rate of doing work. The power of an object in relation to the force and velocity is given by the following equation:

Power (P) = Force (F) × velocity (v)

P = F × v

From the question given above, the following data were obtained:

  • Force (F) = 10 N
  • Velocity (v) = 5 m/s
  • Power (P) =?

P = F × v

P = 10 × 5

<h3>P = 50 W </h3>

Thus, the power that must be delivered to the object by the force is 50 W

Learn more on power: brainly.com/question/19539420

5 0
2 years ago
a flowerpot falls from a windowsill 25m above the sidewalk how fast is the flowerpot moving when it strikes the ground
Mariana [72]

s = 25m

v = ?

a = 9.81m/s²

v² = u² + 2as

v² = 0 + 2x9.81x25

v² = 490.5

v = √490.5

= 22.15m/s

3 0
2 years ago
A man does 500 J of work pushing a car a distance of 2 m. How much force does he apply? Assume there is no friction.
Dmitry [639]

The correct answer is A. 250N

Work is a product of force and distance.

That is, work done=force×distance

Therefore substituting for the values in the question:

500J=force×2m

force= 500Nm/2m=250N

another unit for work done is Nm as force as the SI unit of force is newtons and distance in meters

6 0
3 years ago
Read 2 more answers
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