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Colt1911 [192]
3 years ago
7

La resultante de dos fuerzas perpendiculares aplicadas a un mismo cuerpo es 11.18 N y el módulo de una de ellas es de 10 N. ¿Cuá

l es el módulo de la otra?
Physics
1 answer:
Dmitrij [34]3 years ago
3 0

Answer:

English?

Explanation:

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What do scientists use to determine the temperature of a star?
Nastasia [14]

Answer:

Measure the brightness of a star through two filters and compare the ratio of red to blue light. Compare to the spectra of computer models of stellar spectra of different temperature and develop an accurate color-temperature relation.

7 0
3 years ago
A ball rolling down a hill was displaced 21.9 m while uniformly accelerating from rest. If the final velocity was 7.14 m/s, what
belka [17]

Answer:

a = 1.16 m/s²

Explanation:

In order to find the acceleration of the ball we will use 3rd equation of motion.

2as = Vf² - Vi²

where,

a = acceleration = ?

s = displacement = 21.9 m

Vf = Final Velocity = 7.14 m/s

Vi = Initial Velocity = 0 m/s (Since, ball starts from rest)

Therefore, using the values, we get:

2a(21.9 m) = (7.14 m/s)² - (0 m/s)²

a = (50.97 m²/s²)/(43.8 m)

<u>a = 1.16 m/s²</u>

4 0
3 years ago
HELP ME PLEASE!!!THIS IS SCIENCE!!
emmainna [20.7K]
The very first option is correct, as any other answer is either incorrect in terms of optics or does not stop you from seeing the apple.
4 0
3 years ago
A ball of gas becomes a _____ when nuclear fusion begins in its core.
Nataly [62]
The correct answer is letter A. star. <span>A ball of gas becomes a STAR when nuclear fusion begins in its core.</span>
4 0
3 years ago
A uniform disk with a mass of 5.0 kg and diameter 30 cm rotates on a frictionless fixed axis through its center and perpendicula
Marina86 [1]

Answer:\alpha =10.66 rad/s^2

Explanation:

Given

mass of disk m=5 kg

diameter of disc d=30 cm

Force applied F=4 N

Now this force will Produce  a  torque of magnitude

T=F\cdot r

T=4\dot 0.15

T=0.6 N-m

And Torque is given Product of moment of inertia and angular acceleration (\alpha )

T=I\cdot \alpha

Moment of inertia for Disc I= \frac{Mr^2}{2}

I=0.05625 kg-m^2

0.6=0.05625\cdot \alpha

\alpha =10.66 rad/s^2

3 0
3 years ago
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