The answer would be y=6x+11
D) c=3p+2 3 caterpillars per plant and 2 on ground
Answer:
it should be 2462 feet³
Step-by-step explanation:
Answer:
Step-by-step explanation:
Part A: 176>x>42 because the tem cant be 176 or higher, and it cant be 42 degrees or lower.
Part B: you must describe the graph of inequality
Part C: Because the temperature cannot go below 42 before it freezes, she would not have been able to conduct her research
<h2><u>
Answer with explanation:</u></h2>
Formula to find the confidence interval for population mean :-
![\overline{x}\pm t^*\dfrac{\sigma}{\sqrt{n}}](https://tex.z-dn.net/?f=%5Coverline%7Bx%7D%5Cpm%20t%5E%2A%5Cdfrac%7B%5Csigma%7D%7B%5Csqrt%7Bn%7D%7D)
, where
= sample mean.
t*= critical z-value
n= sample size.
s= sample standard deviation.
By considering the given question , we have
![\overline{x}= 26](https://tex.z-dn.net/?f=%5Coverline%7Bx%7D%3D%2026)
![s=6.2](https://tex.z-dn.net/?f=s%3D6.2)
n= 50
Degree of freedom : df = 49 [ df=n-1]
Significance level : ![\alpha=1-0.95=0.05](https://tex.z-dn.net/?f=%5Calpha%3D1-0.95%3D0.05)
Using students's t-distribution table, the critical t-value for 95% confidence =![t_{\alpha/2,df}=t_{0.025,49}=2.010](https://tex.z-dn.net/?f=t_%7B%5Calpha%2F2%2Cdf%7D%3Dt_%7B0.025%2C49%7D%3D2.010)
Then, 95% confidence interval for the population mean will be :
![26\pm (2.010)\dfrac{6.2}{\sqrt{50}}](https://tex.z-dn.net/?f=26%5Cpm%20%282.010%29%5Cdfrac%7B6.2%7D%7B%5Csqrt%7B50%7D%7D)
![=26\pm (2.010)\dfrac{6.2}{7.0710}](https://tex.z-dn.net/?f=%3D26%5Cpm%20%282.010%29%5Cdfrac%7B6.2%7D%7B7.0710%7D)
![=26\pm (2.010)(0.87682)](https://tex.z-dn.net/?f=%3D26%5Cpm%20%282.010%29%280.87682%29)
![\approx26\pm1.76](https://tex.z-dn.net/?f=%5Capprox26%5Cpm1.76)
![=(26-1.76,\ 26+1.76)=(24.24,\ 27.76)](https://tex.z-dn.net/?f=%3D%2826-1.76%2C%5C%2026%2B1.76%29%3D%2824.24%2C%5C%2027.76%29)
Hence, a 95% confidence interval for the population mean = (24.24, 27.76)
Since 28 is not contained in the above confidence interval , it means it is not reasonable that the population mean is 28 weeks.