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4 years ago

6

Imagine that the moon’s orbit wasn’t elliptical and it that it did not orbit the earth at a 5 degree angle. How would this chang

e the predictability of an eclipse happening every month?

2 answers:

zimovet [89]4 years ago

7 0

Lunar eclipse will happen each month, because of this.

Readme [11.4K]4 years ago

4 0

Answer:

Without the tilt, lunar eclipse will happen every month.

You might be interested in

Calcium carbonate decomposes to form calcium oxide and carbon dioxide, like this:

Leni [432]

Answer: The value of the equilibrium constant Kc for this reaction is 0.088

Explanation:

$Molarity=\frac{x}{M\times V_s}$

where,

x = given mass

M = molar mass

$V_s$ = volume of solution in L

Equilibrium concentration of $CaCO_3$ = $\frac{25.3}{100\times 9.0}=0.028M$

Equilibrium concentration of $CaO$ = $\frac{14.9}{56\times 9.0}=0.029M$

Equilibrium concentration of $CO_2$ = $\frac{33.7}{44\times 9.0}=0.085M$

The given balanced equilibrium reaction is,

$CaCO_3(s)\rightleftharpoons CaO(s)+CO_2(g)$

The expression for equilibrium constant for this reaction will be,

$K_c=\frac{[CaO]\times [CO_2]}{[CaCO_3]}$

Now put all the given values in this expression, we get :

$K_c=\frac{0.029\times 0.085}{0.028}=0.088$

7 0

3 years ago

you have a lead ball with a mass of 420 g. the density of lead is 10.5 g/cm³. what is the volume of the ball

IrinaK [193]

Answer:

The answer is

<h2>40.0 mL</h2>

Explanation:

The volume of a substance when given the density and mass can be found by using the formula

$volume = \frac{mass}{density}$

From the question

mass = 420 g

density = 10.5 g/cm³

The volume is

$volume = \frac{420}{10.5} \\$

We have the final answer as

<h3>40.0 mL</h3>

Hope this helps you

7 0

3 years ago

How many grams of Al(no2)3 should be added to 1.3L of water to prepare a 2.0M solution

Virty [35]

Answer: 429 grams of $Al(NO_2)_3$ should be added to 1.3 L of water to prepare 2.0 M solution

Explanation:

Molarity of a solution is defined as the number of moles of solute dissolved per Liter of the solution.

$Molarity=\frac{n}{V_s}$

where,

n = moles of solute $Al(NO_2)_3$ = $\frac{\text {given mass}}{\text {Molar mass}}=\frac{xg}{165g/mol}$

$V_s$ = volume of solution in Liters

Now put all the given values in the formula of molarity, we get

$2.0M=\frac{xg}{165g/mol\times 1.3L}$

$x=429g$

Therefore, 429 grams of $Al(NO_2)_3$ should be added to 1.3 L of water to prepare 2.0 M solution

3 0

3 years ago

How many moles are in a 13.7g block of calcium?

goldenfox [79]

<h3>Answer:</h3>

0.342 mol Ca

<h3>General Formulas and Concepts:</h3>

<u>Math</u>

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right<u> </u>

<u>Chemistry</u>

<u>Atomic Structure</u>

Reading a Periodic Table

<u>Stoichiometry</u>

Using Dimensional Analysis

<h3>Explanation:</h3>

<u>Step 1: Define</u>

13.7 g Ca

<u>Step 2: Identify Conversions</u>

Molar Mass of Ca - 40.08 g/mol

<u>Step 3: Convert</u>

Set up: $\displaystyle 13.7 \ g \ Ca(\frac{1 \ mol \ Ca}{40.08 \ g \ Ca})$
Multiply/Divide: $\displaystyle 0.341816 \ mol \ Ca$

<u>Step 4: Check</u>

<em>Follow sig fig rules and round. We are given 3 sig figs.</em>

0.341816 mol Ca ≈ 0.342 mol Ca

6 0

3 years ago

Which state of matter is this?<br>-liquid<br>-amorphous liquid<br>-gas<br>-crystalline solid

PilotLPTM [1.2K]

Gaseous

The atoms are taking up the volume of the entire container

8 0

3 years ago