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maria [59]
3 years ago
13

Which pair of atoms would form a covalent bond ?

Chemistry
2 answers:
Liula [17]3 years ago
7 0
I think O and Cl will form covalent bonds since they are both non-metals and don't have a large enough difference in electronegativities to create an ionic bond.

I hope this helps.  Let me know if anything is unclear.
NeTakaya3 years ago
4 0
<h2>Answer:</h2>

oxygen (O) and chlorine (Cl).

<h2>Explanation:</h2>

As the electronegativity value of an element increases It is more likely to make an ionic bond. e.g. the metallic elements. On the moderate values of electronegativity, elements tend to make covalent bond.

Oxygen and chlorine will make covalent bond because the electronegativity difference between these two elements is 0,5 so there bond will be covalent in nature.

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Which of the following changes to a pipe would increase the conductance by a factor of 12?
ivanzaharov [21]

C. Tripling the length and reducing the radius by a factor of 2 is the change to a pipe would increase the conductance by a factor of 12.

<u>Explanation:</u>

As we know that the resistance is directly proportional to the length of the pipe and it is inversely proportional to the cross sectional area of the pipe.

So it is represented as,

R∝ l /A [ area is radius square]

So k is the proportionality constant used.

R = kl/A

Conductance is the inverse of resistance, so it is given as,

C= 1/R.

R₁ = kl₁ / A₁

R₂ = kl₂/A₂

R₂/R₁ = 1/12 [∵ conductance is the inverse of resistance]

        = l₂A₁ / l₁A₂

If we chose l₁/l₂= 3 and A₂/A₁= 4 So R₂/R₁= 1/3×4 = 1/12

So tripling the length and reducing the radius by a factor of 2 would increase the conductance by a factor of 12.

6 0
2 years ago
What did J. J. Thomson observe when he applied electric voltage to a cathode ray tube in his famous experiment?
irinina [24]
QUICK ANSWER

J.J. Thomson's cathode ray experiment was a set of three experiments that assisted in discovering electrons. He did this using a cathode ray tube or CRT. It is a vacuum sealed tube with a cathode and anode on one side. 

7 0
2 years ago
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CN- is a Bronsted - Lowry base. What will this substance form when it accepts a proton?
sergejj [24]
It will form HCN Hydrogen Cyanide.
8 0
2 years ago
i need help i have a homework assignment to finish and this is the last question help please and thank u
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5 0
2 years ago
A 25.00-mL aliquot of a nitric acid solution of unknown concentration is pipetted into a 125-mL Erlenmeyer flask and 2 drops of
Semenov [28]

Answer:

0.0611M of HNO3

Explanation:

<em>The concentration of the NaOH solution must be 0.1198M</em>

<em />

The reaction of NaOH with HNO3 is:

NaOH + HNO3 → NaNO3 + H2O

<em>1 mole of NaOH reacts per mole of HNO3.</em>

That means the moles of NaOH used in the titration are equal to moles of HNO3.

<em>Moles HNO3:</em>

12.75mL = 0.01275L * (0.1198mol / L) = 0.0015274 moles NaOH = Moles HNO3.

In 25.00mL = 0.025L -The volume of the aliquot-:

0.00153 moles HNO3 / 0.025L =

<h3> 0.0611M of HNO3</h3>
7 0
3 years ago
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