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Otrada [13]
3 years ago
15

Is this correct?????? Pls helpppp :)

Chemistry
2 answers:
Crank3 years ago
7 0

Answer:

i think all is correct but maybe switch 3 and 11? to me it makes way more sense.

Explanation:

shepuryov [24]3 years ago
6 0
It's correct just switch 3 and 11
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a 3.50L sample of neon gas has a pressure of .950atm at 20c what would the volume be if the pressure increased to 1.50atm and th
ehidna [41]

Answer:

V_2=2.22L

Explanation:

Hello,

In this case, we use the Boyle's law which allows us to understand the volume-pressure behavior as an inversely proportional relationship:

P_1V_1=P_2V_2

Thus, solving for the final volume, once the pressure changes, we obtain:

V_2=\frac{P_1V_1}{P_2}=\frac{3.50L*0.950atm}{1.50atm}  \\\\V_2=2.22L

Best regards.

8 0
4 years ago
The second-order rate constant for the dimerization of a protein (P) P + P → P2 is 6.2 × 10−3/M · s at 25°C. Part 1 out of 2 If
siniylev [52]

Answer:

r=1.59\times 10^{-10}\ M/s

Explanation:

According to the law of mass action:-

The rate of the reaction is directly proportional to the active concentration of the reactant which each are raised to the experimentally determined coefficients which are known as orders. The rate is determined by the slowest step in the reaction mechanics.

Order of in the mass action law is the coefficient which is raised to the active concentration of the reactants. It is experimentally determined and can be zero, positive negative or fractional.

The order of the whole reaction is the sum of the order of each reactant which is raised to its power in the rate law.

From the reaction given that:-

P+P\rightarrown P_2

The expression for the rate is:-

r=k[P]^2

Given that;- k= 6.2\times 10^{-3} /Ms

[P] = 1.6\times 10^{-4} M

Thus,

r=6.2\times \:10^{-3}\times \:\left(1.6\times \:\:10^{-4}\right)^2\ M/s=1.59\times 10^{-10}\ M/s

8 0
3 years ago
Given the two reactions PbCl2(aq)⇌Pb2+(aq)+2Cl−(aq), K3 = 1.89×10−10, and AgCl(aq)⇌Ag+(aq)+Cl−(aq), K4 = 1.25×10−4, what is the
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Answer:

1.2\times 10^{-2}

Explanation:

The given reactions are:

PbCl2(aq)⇌Pb2+(aq)+2Cl−(aq)     K_3 = 1.89\times 10^{-10}

AgCl(aq)⇌Ag+(aq)+Cl−(aq)           K_4 = 1.25\times 10^{-4}

Required reaction is:

PbCl2(aq)+2Ag+(aq)⇌2AgCl(aq)+Pb2+(aq)

K_f = \frac{K_3}{K_4^2}\\=\frac{1.89\times 10^{-10}}{1.25\times 10^{-4}}^2\\=1.2\times 10^{-2}

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4 years ago
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C would be the only logical answer if you really think about what it’s saying about the instrument.
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