Hey!
A function in slope-intercept form would look like y=mx+b; with the x and y values on the opposites of the equation.
A function in standard form would look like ax+by=c; with the x and y values on the same side of the equation.
Hope this helps!
Answer:
D. y = -1/5x +32/5
Step-by-step explanation:
The equation of the line passing through point (h, k) with slope m can be written ...
y = m(x -h) +k
Filling in your given values, the equation is ...
y = -1/5(x -(-3)) +7
y = -1/5x -3/5 +7 . . . . eliminate parentheses
y = -1/5x +32/5 . . . . . combine constants
Answer:
y = 2x + 3
Step-by-step explanation:
The y-intercept is clearly marked: it's b = 3 (or 0, 3).
Going from the point (-3, -3) to the point (0, 3),
x increases by 3 and y increases by 6. Thus, the slope of the line through these two points is m = rise / run = 6 / 3, or m = 2.
Starting with the slope-intercept form of the equation of a straight line:
y = mx + b, we substitute 2 for m and 3 for b, obtaining:
y = 2x + 3
Answer:-7
Step-by-step explanation:
Answer:
×=30⁰ :)
Step-by-step explanation:
x⁰+(x+30⁰)= 90⁰
x⁰+x⁰= 90⁰-30⁰=60⁰
2x⁰=60⁰
60⁰÷2=30⁰ => x⁰=30⁰
verification:
30⁰+(30⁰+30⁰)=90⁰
