Answer:
A.) 8 m/s
B.) 7.0 m
Explanation:
Given that a block is given an initial velocity of 8.0 m/s up a frictionless 28° inclined plane.
(a) What is its velocity when it reaches the top of the plane?
Since the plane is frictionless, the final velocity V will be the same as 8 m/s
The velocity will be 8 m/s as it reaches the top of the plane.
(b) How far horizontally does it land after it leaves the plane?
For frictionless plane,
a = gsinø
Acceleration a = 9.8sin28
Acceleration a = 4.6 m/s^2
Using the third equation of motion
V^2 = U^2 - 2as
Substitute the a and the U into the equation. Where V = 0
0 = 8^2 - 2 × 4.6 × S
9.2S = 64
S = 64/9.2
S = 6.956 m
S = 7.0 m
The Impulse delivered to the baseball is 89 kgm/s.
To solve the problem above, we use the formula of impulse.
⇒ Formula:
- I = m(v-u)................. Equation 1
Where:
- I = Impulse delivered to the baseball
- m = mass of the baseball
- v = Final velocity of the baseball
- u = initial speed of the baseball
From the question,
⇒ Given:
- m = 0.8 kg
- u = 67 m/s
- v = -44 m/s
⇒ Substitute these values into equation 1
- I = 0.8(-44-67)
- I = 0.8(-111)
- I = -88.8
- I ≈ -89 kgm/s
Note: The negative tells that the impulse is in the same direction as the final velocity and therefore can be ignored.
Hence, The Impulse delivered to the baseball is 89 kgm/s.
Learn more about impulse here: brainly.com/question/7973509
Answer:
center of mass of the two masses will lie at x = 2.52 cm
center of gravity of the two masses will lie at x = 2.52 cm
So center of mass is same as center of gravity because value of gravity is constant here
Explanation:
Position of centre of mass is given as

here we have




now we have



so center of mass of the two masses will lie at x = 2.52 cm
now for center of gravity we can use

here we have




now we have



So center of mass is same as center of gravity because value of gravity is constant here
Electrical Energy because the electrons in the battery travel from out one end of the battery through a circuit and back to the other end
Image formed by a plane mirror is always virtual which means that the light rays do not actually come from the image but upright and these of the same shape and size are the object it is<span> reflecting.</span>