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1 year ago

A recreational flyer does not need an airspace authorization in which type of airspace?.

Physics

1 answer:

finlep [7]1 year ago

5 0

A recreational flyer does not need an airspace authorization in uncontrolled airspace.

An airspace in which the Air Traffic Control service is not considered necessary is called uncontrolled airspace.

In general, an uncontrolled airspace remains at 400 or under 400 levels surpassing the ground.

Moreover, in an uncontrolled airspace the recreational flyer does not need any prior authorization and should also have particular knowledge about the airport traffic patterns

To put it simply, the remote pilots and flyers are not allowed to use landing and take off areas in an uncontrolled airspace.

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You set your stationary bike on a high 80-N friction-like resistive force and cycle for 30 min at a speed of 8.0 m/s . Your body

stellarik [79]

A) The change in internal chemical energy is $1.15\cdot 10^7 J$

B) The time needed is 1 minute

Explanation:

First of all, we start by calculating the power output of you and the bike, given by:

$P=Fv$

where

F = 80 N is the force that must be applied in order to overcome friction and travel at constant speed

v = 8.0 m/s is the velocity

Substituting,

$P=(80)(8.0)=640 W$

The energy output is related to the power by the equation

$P=\frac{E}{t}$

where:

P = 640 W is the power output

E is the energy output

$t = 30 min \cdot 60 = 1800 s$ is the time elapsed

Solving for E,

$E=Pt=(640)(1800)=1.15\cdot 10^6 J$

Since the body is 10% efficient at converting chemical energy into mechanical work (which is the output energy), this means that the change in internal chemical energy is given by

$\Delta E = \frac{E}{0.10}=\frac{1.15\cdot 10^6}{0.10}=1.15\cdot 10^7 J$

From the previous part, we found that in a time of

t = 30 min

the amount of internal chemical energy converted is

$E=1.15\cdot 10^7 J$

Here we want to find the time t' needed to convert an amount of chemical energy of

$E'=3.8\cdot 10^5 J$

So we can setup the following proportion:

$\frac{t}{E}=\frac{t'}{E'}$

And solving for t',

$t'=\frac{E't}{E}=\frac{(3.8\cdot 10^5)(30)}{1.15\cdot 10^7}=1 min$

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3 years ago

What happens when a hurricane makes landfall? A. A hurricane will weaken after making landfall. B. A hurricane will pick up spee

kotykmax [81]

Answer:

Explanation:

it has no more water to make it bigger

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3 years ago

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There is little vertical air movement in the __ because of the cold, heavy air at the bottom of the layer.

pogonyaev

The correct answer is the Mesosphere. <span>Mesosphere </span><span>is the layer of the Earth's atmosphere that is directly above the stratopause and directly below the mesopause.</span>

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3 years ago

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What circumstance would allow an officer to search a home even if they didn’t have a warrant?

Ipatiy [6.2K]

Answer:

Explanation:

The officer would have had permission regardless of anything else, kind of like letting someone into your house.

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3 years ago

The acceleration due to gravity on the surface of Mars is about one-third the acceleration due to gravity on Earthâ€™s surface.

aksik [14]

Answer:

one-third of its weight on Earth's surface

Explanation:

Weight of an object is = W = m*g

Gravity on Earth = g₁ = 9.8 m/s

Gravity on Mars = g₂ = $\frac{1}{3}$ g₁

Weight of probe on earth = w₁ = m * g₁

Weight of probe on Mars = w₂ = m * g₂ -------- ( 1 )

As g₂ = g₁/3 --------- ( 2 )

Put equation (2) in equation (1)

Weight of probe on Mars = w₂ = m * g₁ /3

Weight of probe on Mars = $\frac{1}{3}$ m * g₁ = $\frac{1}{3}$ w₁

⇒Weight of probe on Mars = $\frac{1}{3}$ Weight of probe on earth

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