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Illusion [34]
3 years ago
13

Note: Take East as the positive direction. A(n) 81 kg fisherman jumps from a dock into a 128 kg rowboat at rest on the West side

of the dock. If the velocity of the fisherman is 4.5 m/s to the West as he leaves the dock, what is the final velocity of the fisherman and the boat? Answer in units of m/s.
Physics
1 answer:
Blizzard [7]3 years ago
6 0

Answer:

final velocity of fisherman will be 1.744 m /sec in west direction

Explanation:

We have given mass of the fisherman m_1=81kg

Velocity of fisherman v_=-4.5m/sec ( As east direction is positive direction )

Mass of the rowboat m_2=128kg

As the rowboat is at rest so v_2=0m/sec

Now according to conservation of momentum

m_1v_1+m_2v_2=(m_1+m_2)v

81\times -4.5+128\times 0=(81+128)\times v

v=-1.744m/sec

So final velocity of fisherman will be 1.744 m /sec in west direction

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