Question

Note: Take East as the positive direction. A(n) 81 kg fisherman jumps from a dock into a 128 kg rowboat at rest on the West side of the dock. If the velocity of the fisherman is 4.5 m/s to the West as he leaves the dock, what is the final velocity of the fisherman and the boat? Answer in units of m/s.

Answer 1

Answer:

final velocity of fisherman will be 1.744 m /sec in west direction

Explanation:

We have given mass of the fisherman $m_1=81kg$

Velocity of fisherman $v_=-4.5m/sec$ ( As east direction is positive direction )

Mass of the rowboat $m_2=128kg$

As the rowboat is at rest so $v_2=0m/sec$

Now according to conservation of momentum

$m_1v_1+m_2v_2=(m_1+m_2)v$

$81\times -4.5+128\times 0=(81+128)\times v$

$v=-1.744m/sec$

So final velocity of fisherman will be 1.744 m /sec in west direction