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Alex Ar [27]
4 years ago
7

The term of the geometric sequence always increasesA.TrueB.false

Mathematics
2 answers:
Sladkaya [172]4 years ago
6 0

Answer:

she's right, its false

Step-by-step explanation:

zimovet [89]4 years ago
4 0

False

If the value is .56 for example the geometric term will decrease

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pogonyaev
120 in 2 minutes is 60 per minute so 60x5 is 300
Answer:300
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(2 x 10^4) + (7 X 10^4) =
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Quick what does ^ mean I can solve that but I need to know what ^ means.
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Find the other endpoint of the line segment with the given endpoint and midpoint.
Shtirlitz [24]

Answer:

endpoint is (29, -13)

Step-by-step explanation:

Formula for midpoint is (\frac{x_{1} + x_{2} }{2} ,\frac{y_{1} + y_{2}  }{2} )

So, let (x_{2} , y_{2} ) be the coordinates of the endpoint you are looking for.

x_{1} = -9  and y_{1}  = 7

(\frac{-9 + x_{2} }{2} , \frac{7 + y_{2} }{2} ) = (10, -3)

\frac{-9 + x_{2} }{2}  = 10           \frac{7 + y_{2} }{2}  = -3

-9 + x_{2} = 20         7 + y_{2}  = -6

x_{2}  =  29                    y_{2}  = -13

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6 0
3 years ago
A padlock has the digits 0 through 9 arranged in a circle on its face. A combination for 0 1 2 3 4 6 5 7 8 9 this padlock is fou
stepan [7]

Answer:

The total numbers of possible combinations are 3430.

Step-by-step explanation:

Consider the provided information.

A combination for 0 1 2 3 4 6 5 7 8 9 this padlock is four digits long. Because of the internal mechanics of the lock, no pair of consecutive numbers in the combination can be the same or one place apart on the face.

Here, for the first digit we have 10 choices.

For the second digit we have 7 choices, as the digit can't be the same nor adjacent to the first digit.

For the third digit we have 7 choices, as the digit can't be the same nor adjacent to the second digit.

For the fourth digit we have 7 choices, as the digit can't be the same nor adjacent to the third digit.

So the number of choices are:

10\times 7\times 7\times 7=10\times 7^3\\10\times 343=3430

Hence, the total numbers of possible combinations are 3430.

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To regroup is to use place value to exchange equal amount when renaming a number.
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