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miv72 [106K]
4 years ago
7

How much heat energy is tequired to raise the temperature of 3 kg of copper from 0

Physics
1 answer:
rusak2 [61]4 years ago
6 0

2 would be the answer

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A car starts from rest and accelerates uniformly over a time of 5.37 seconds for a distance of 101 m. Determine the acceleration
castortr0y [4]

Answer:

8.10m s-2

Explanation:

8 0
4 years ago
The first jeans, made by Levi Strauss & Co., were invented in which year?
galina1969 [7]

Answer:

1873

Explanation:

The next time you see someone wearing a pair of Levi's® jeans, remember that these pants are a direct descendant of that first pair made back in 1873. That year, two visionary immigrants — Levi Strauss and Jacob Davis — turned denim, thread and a little metal into what has become the most popular apparel on earth.

6 0
3 years ago
Read 2 more answers
If an equation is demensionally correct does this mean that the equation is true
DerKrebs [107]

Explanation:

If an equation is dimensionally correct, it does not mean that the equation must be true. On the other hand, when the equation is dimensionally correct, the equation cannot be true. Dimensional analysis is a technique used to check whether a relationship is correct

7 0
3 years ago
Imagine that you pushed a box, applying a force of 60 newtons, over a distance of 4 meters. How much would you have done?
grin007 [14]
You would have done 240 joules of work on the box.

Work = (force)  x  (distance)

         =  (60 newtons)  x  (4 meters)

         =         240 joules  . 
5 0
3 years ago
What is the final temperature when a 3.0 kg gold bar at 99 0C is dropped into 0.22 kg of water at 25oC?
liq [111]

Answer:

46.9 C

Explanation:

The heat released by the gold bar is equal to the heat absorbed by the water:

m_g C_g (T_g-T_f)=m_w C_w (T_f-T_w)

where:

m_g = 3.0 kg is the mass of the gold bar

C_g=129 J/kg C is the specific heat of gold

T_g=99 C is the initial temperature of the gold bar

m_w = 0.22 kg is the mass of the water

C_w=4186 J/kg C is the specific heat of water

T_w=25 C is the initial temperature of the water

T_f is the final temperature of both gold and water at equilibrium

We can re-arrange the formula and solve for T_f, so we find:

m_g C_g T_g -m_g C_g T_f = m_w C_w T_f - m_w C_w T_w\\m_g C_g T_g +m_w C_w T_w= m_w C_w T_f +m_g C_g T_f \\T_f=\frac{m_g C_g T_g +m_w C_w T_w}{m_w C_w + m_g C_g}=\\=\frac{(3.0)(129)(99)+(0.22)(4186)(25)}{(0.22)(4186)+(3.0)(129)}=\frac{38313+23023}{921+387}=\frac{61336}{1308}=46.9 C

5 0
3 years ago
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