Plane 1 leaves city A at 7 am and flies at a speed of 250 mph in a straight line towards city B, located 1000 miles North of cit
1 answer:
Answer:v=142.85 mph
Explanation:
Given
Distance between two cities is 1000 miles
Speed of plane 1 id 250 mph
Plane 1 leaves at 7 am and Plane 2 leaves at 7:30 am
They will collide if plane 2 travels 300 miles and Plane 1 travels 400 miles in t and t+0.5 hr respectively
Time taken by plane 2
----1
time taken by plane 1 to travel 400 miles
-----2
substitute value of t in 2
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Remember that moment before collision is equal to the moment after collision.
Plugging in our values,
Answer:
(a)
(b)
1120 N
Explanation:
Change in velocity, is given by subtracting the initial velocity from the final velocity and expressed as
Where v represent the velocity and subscripts f and i represent final and initial respectively. Since the ball finally comes to rest, its final velocity is zero. Substituting 0 for final velocity and the given figure of 8 m/s for initial velocity then the change in velocity is given by
To find then we substitute 7 kg for m and -8 m/s for
therefore
(b)
The impact force, F is given as the product of mass and acceleration. Here, acceleration is given by dividing the change in velocity by time ie
Substituting t with 0.05 s then
Since F=ma then substituting m with 7 Kg we get that F=7*-160=-1120 N
Therefore, the impact force is equivalent to 1120 N