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2 years ago

The total energy of a 0.050 kg object travelling at 0.70 c is:

Physics

2 answers:

Elena L [17]2 years ago

8 0

Answer:

1.1025×10^15Joules

No correct option

Explanation:

The type of energy possessed by the object is kinetic energy. Kinetic energy is the energy due to virtue of an object motion.

KE = 1/2MV² where;

M is the mass of the car = 0.05kg

V is the velocity of the car

Since the car is traveling at 0.7c (c is the speed of light)

speed = 0.7c { 0.7(3×10^8)}

Speed = 2.1×10^8

Substituting this values in the formula given we have;

KE = 1/2×0.05×(2.1×10^8)²

KE = 1.1025×10^15Joules

No correct option.

finlep [7]2 years ago

3 0

What is the unit c denotes here

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A plane flies from base camp to lake a, a distance of 290 km at a direction of 20.0° north of east. after dropping off supplies,

Alchen [17]

We can simply find components of the given directions and conveniently add them up to find the total distance.

290 km 20 deg north of east can be decomposed as :

290 x cos(20) EAST + 290 sin(20) NORTH

=272.5 E + 99.18 N

Now from this point ,

170 Km 30 deg west of north :

170 cos(30) N - 170 sin (30) E [ east = - west]

= 147.22 N - 85 E

hence coordinates of lake b are

(272.5 - 85) E + (99.18 + 147.22)N

187.5 E +264.4 N

use right triangle property to find distance D = $\sqrt{a^2 + b^2}$

D = 324.13 Km

and angle = atan(b/a) = 54.65 deg

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3 0

3 years ago

The line spectrum of lithium has a red line at 670.8 nm. Calculate the energy of a photon with this wavelength.

Vadim26 [7]

First of all, we can calculate the frequency of the photon, which is related to the wavelength by the following equation:
$f= \frac{c}{\lambda}$
where c is the speed of light and $\lambda=670.8 nm=670.8 \cdot 10^{-9} m$ is the photon wavelength. Substituting into the formula, we find the frequency
$f= \frac{c}{\lambda}= \frac{3 \cdot 10^8 m/s}{670.8 \cdot 10^{-9} m}=4.47 \cdot 10^{14} Hz$

Now we can find the energy of the photon with the following equation:
$E=hf$
where h is the Planck constant. Substituting numbers, we find
$E=hf=(6.6 \cdot 10^{-34}Js)(4.47 \cdot 10^{14} Hz)=2.95 \cdot 10^{-19} J$

5 0

3 years ago

Objects A and B, of mass M and 2M respectively, are each pushed a distance d straight up an inclined plane by a force F parallel

krek1111 [17]

Answer:

The correct answer is <u>option (A) that is KEA > KEB .</u>

Explanation:

Let us calculate -

If the object is straighten up and inclined plane , the work done is

$W=F_d- F_f_r_id-F_gh$