The total energy of a 0.050 kg object travelling at 0.70 c is:
2 answers:
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Answer:
<em>The canyon is approximately 314 meters away</em>
Explanation:
<u>Speed of Sound</u>
If we emit sounds in an open space where a large obstacle (like a mountain) is expected to return the sounds, then it will travel forth and back at a given speed for a certain time. We can assume the speed of sound is constant, so we could know the approximate distance of the mountain (or canyon in our case) by the known formula.
Where is the speed of sound and t is half the time we hear our echo.
The speed of sound in m/s can be calculated from the approximate formula in terms of the temperature T in degrees Celsius
We have , so
Let's compute x, for t=1.8/2=0.9 seconds
The canyon is approximately 314 meters away
Answer:
42.86m
Explanation:
The first thing we should keep in mind is that the watermelon moves with uniform acceleracion equal to gravity (9.81m / s ^ 2)
A body that moves with constant acceleration means that it moves in "a uniformly accelerated motion", which means that if the velocity is plotted with respect to time we will find a line and its slope will be the value of the acceleration, it determines how much it changes the speed with respect to time.
When performing a mathematical demonstration, it is found that the equations that define this movement are as follows.
where
Vf=29m/s= final speed
Vo= initial speed=0m/S
g=gravity=9.81m/s^2
Y= distance traveled(m)
solving
the distance traveled by watermelon is 42.86m